Model 6 Efficiency of the worker Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on time & work topic of quantitative aptitude
(a) 15 days
(b) 14 days
(c) 13 days
(d) 20 days
The correct answers to the above question in:
Answer: (a)
Using Rule 2,
Time taken by A to complete the work = x days
Time taken by B to complete the work = 3x days
So, 3x - x = 2x = 40
x = 20 and 3x = 60
(A + B)’s 1 day’s work
= $1/20 + 1/60 = {3 + 1}/60 = 4/60 = 1/15$
A and B together will complete the work in 15 days.
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Read more efficiency of the worker Based Quantitative Aptitude Questions and Answers
Question : 1
A is twice as good a workman as B and B is twice as good a workman as C. If A and B can together finish a piece of work in 4 days, then C can do it by himself in
a) 12 days
b) 6 days
c) 8 days
d) 24 days
Answer »Answer: (d)
Using Rule 2,
According to the question,
If A takes x days to complete the work, B will take 2x days and C will take 4x days,
Now, (A + B)'s 1 day’s work = $1/4$
$1/x + 1/{2x} = 1/4 ⇒ {2 + 1}/{2x} = 1/4$
2x = 12 ⇒ x = 6
C will complete the work in 4x i.e. 24 days.
Question : 2
A can do a certain job in 12 days. B is 60% more efficient than A. To do the same job B alone would take :
a) 7 days
b) 7$1/2$ days
c) 8 days
d) 10 days
Answer »Answer: (b)
Time taken by B
= $12 × 100/160 = 15/2 = 7{1}/2$ days
Using Rule 17,
Here, x = 12, R = 60%
Time taken by B = $x × 100/{100 + R}$ days
= $12 × 100/160$ days
= $15/2$ days = 7$1/2$ days
Question : 3
A can do a certain work in 12 days. B is 60% more efficient than A. How many days will B and A together take to do the same job?
a) $60/13$ days
b) $80/13$ days
c) $70/13$ days
d) $75/13$ days
Answer »Answer: (a)
Time taken by B in completing the work
=$12 × 100/160 = 15/2$ days
(A+B)’s 1 day’s work
= $1/12 + 2/15 = {5 + 8}/60 = 13/60$
Hence, the work will be completed in $60/13$ days
Using Rule 17,
Here, x = 12, R = 60%
Time taken by B= $x × 100/{100 + R}$ days
= $12 × 100/160$ days = $15/2$ days
Now using Rule 2,
Time taken by A and B = ${xy}/{x + y}$
= ${12 × {15/2}}/{12 + {15/2}}$
= ${12 × 15}/39 = 60/13$ days
Question : 4
To complete a work, A takes 50% more time than B. If together they take 18 days to complete the work, how much time shall B take to do it ?
a) 45 days
b) 30 days
c) 35 days
d) 40 days
Answer »Answer: (b)
Using Rule 2If A completes a piece of work in 'x' days, and B completes the same work in 'y' days, then,Work done by A in 1 day = $1/x$, Work done by B in 1 day = $1/y$ Work done by A and B in 1 day = $1/x + 1/y = {x + y}/{xy}$Total time taken to complete the work by A and B both = $({xy}/{x + y})$
Let B alone can do the work in x days.
A can do the work in ${3x}/2$ days.
According to the question,
$1/x + 2/{3x} = 1/18 ⇒ {3 + 2}/{3x} = 1/18$
$5/{3x} = 1/18 ⇒ 3x = 18 × 5$
$x = {18 × 5}/3$ = 30 days
Question : 5
A is 30% more efficient than B, and can alone do a work in 23 days. The number of days, in which A and B, working together can finish the job is
a) 21 days
b) 11 days
c) 13 days
d) 20 days
Answer »Answer: (c)
Using Rule 2,
Time taken by B
= $130/100 × 23 = 299/10$ days
(A + B)’s 1 day’s work
= $1/23 + 10/299$
= ${13 + 10}/299 = 23/299 = 1/13$
Time taken by (A + B) = 13 days
Question : 6
Shashi can do a piece of work in 20 days. Tanya is 25% more efficient than Shashi. The number of days taken by Tanya to do the same piece of work is :
a) 25
b) 15
c) 16
d) 18
Answer »Answer: (c)
Time taken by Shashi in doing 1 work = 20 days
Tanya is 25% more efficient than Shashi.
Time taken by Tanya
= $100/125 × 20$ = 16 days
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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