Model 7 Working With Individual Wages Practice Questions Answers Test With Solutions & More Shortcuts

Question : 1 [SSC (South Zone) Investigator 2010]

20 men or 24 women can complete a piece of work in 20 days. If 30 men and 12 women undertake to complete the work, the work will be completed in

a) 16 days

b) 15 days

c) 10 days

d) 12 days

Answer: (c)

20 men ≡ 24 women

5 men ≡ 6 women

30 men + 12 women = 40 men

$M_1D_1 = M_2D_2$

20 × 20 = 40 × $D_2$

$D_2 = {20 × 20}/40$ = 10 days

Using Rule 12
If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work in
Time taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days

Here, A = 20, B = 24, a = 20

$A_1 = 30, B_1$ = 12

Required time = ${a(A . B)}/{A_1B + B_1A}$

= ${20(20 × 24)}/{30 × 24 + 12 × 20}$

= $9600/{720 + 240} = 9600/960$ = 10 days

Question : 2 [SSC CGL Tier-I 2010]

7 men can complete a piece of work in 12 days. How many additional men will be required to complete double the work in 8 days ?

a) 7

b) 14

c) 28

d) 21

Answer: (b)

WorkDaysMen
1127
28x

∴ ${1 : 2}/{8 : 12}]$ : : 7 : x

where, x is no. of men

1 × 8 × x = 2 × 12 × 7

$x = {7 × 12 × 2}/8 = 21$

Number of additional men = 21 - 7 = 14

Metod 2 : Using Rule 1,

$M_1D_1W_2 = M_2D_2W_1$

7 × 12 × 2 = $M_2$ × 8 × 1

$M_2 = {7 × 12 × 2}/8 = 21$

No. of additional men = 21 - 7 = 14

Question : 3 [SSC CPO S.I.2006]

Two persons can complete a piece of work in 9 days. How many more persons are needed to complete double the work in 12 days?

a) 1

b) 4

c) 3

d) 2

Answer: (c)

WorkDaysPersons
192
212x

where x = number of persons

∴ ${1 : 2}/{12 : 9}]$ : : 2 : x

1×12 × x = 2 × 9 × 2

$x = {2 × 9 × 2}/12$ = 3

Using Rule 1,

Here, $M_1 = 2, W_1 = 1, D_1$ = 9

$M_2 = ?, W_2 = 2, D_2$ = 12

$M_1D_1W_2 = M_2D_2W_1$

2 × 9 × 2 = $M_2$ × 12 × 1

$M_2 = 36/12$ = 3

Question : 4 [SSC CGL Prelim 2003]

If 72 men can build a wall of 280 m length in 21 days, how many men could take 18 days to build a similar type of wall of length 100 m?

a) 28

b) 18

c) 30

d) 10

Answer: (c)

Using Rule 1,

We know that

$W_1/{M_1D_1} = W_2/{M_2D_2}$

$280/{72 × 21} = 100/{x × 18}$

Where x = number of men

x × 18 × 280 = 100 × 72 × 21

$x = {100 × 72 × 21}/{18 × 280}$ = 30

Question : 5 [SSC CGL Tier-I 2015]

If 4 men or 8 women can do a piece of work in 15 days, in how many days can 6 men and 12 women do the same piece of work ?

a) 30 days

b) 15 days

c) 20 days

d) 5 days

Answer: (d)

4 men ≡ 8 women

1 man ≡ 2 women

6 men + 12 women

≡ 12 women + 12 women ≡ 24 women

$M_1D_1 = M_2D_2$

8 × 15 = 24 × $D_2$

$D_2 = {8 × 15}/24$ = 5 days

Using Rule 12,

Here, A = 4, B = 8, a = 15

$A_1 = 6, B_1$ = 12

Required number of days = ${a(A . B)}/{A_1B + B_1A}$

= ${15(4 × 8)}/{6 × 8 + 12 × 4}$

= ${15 × 32}/96$ = 5 days

IMPORTANT QUANTITATIVE APTITUDE EXERCISES

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