Model 6 Efficiency of the worker Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 31 [SSC CGL Tier-I 2013]
A can do a piece of work in 6 days. B is 25% more efficient than A. How long would B alone take to finish this work?
a) 2$2/3$ days
b) 4$4/5$ days
c) 3$1/3$ days
d) 5$1/4$ days
Answer »Answer: (b)
Ratio of A's and B's efficiency = 4 : 5
Ratio of time taken = 5 : 4
Time taken by B = ${6 × 4}/5$
= $24/5 = 4{4}/5$ days
Using Rule 17,
Here, x = 6, R = 25%
Time taken by B = $x × 100/{100 + R}$ days
= $6 × 100/125 = 6 × 4/5$
= $24/5 = 4{4}/5$ days
Question : 32 [SSC CGL Tier-I 2016]
A works twice as fast as B. If B can complete a piece of work independently in 12 days, then what will be the number of days taken by A and B together to finish the work?
a) 18
b) 4
c) 6
d) 8
Answer »Answer: (b)
A is twice efficient than B.
Time taken by B = 12 days
Time taken by A = 6 days
(A + B)’s 1 day’s work
= $1/6 + 1/12 = {2 + 1}/12 = 1/4$
∴ Required time = 4 days
Question : 33 [SSC CGL Tier-1 2011]
A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in
a) 7 days
b) 5$2/3$ days
c) 6$2/3$ days
d) 6 days
Answer »Answer: (c)
If B alone completes the work in x days, A will do the same in 2x days.
(A + B)’s 1 day’s work = $1/x + 1/{2x} = {2 + 1}/{2x} = 3/{2x}$
and C’s 1 day’s work = $3/{4x}$
$3/{4x} = 1/20$
4x = 3 × 20
$x = {3 × 20}/4 = 15$
(A + B + C)’s 1day’s work
= $1/{2x} + 1/x + 3/{4x} = 1/30 + 1/15 + 1/20$
= ${2 + 4 + 3}/60 = 9/60 = 3/20$
Hence, all three together will complete the work in
$20/3$ or $6{2}/3$ days.
Question : 34 [SSC CHSL 2011]
A takes 10 days less than the time taken by B to finish a piece of work. If both A and B can do it in 12 days, then the time taken by B alone to finish the work is
a) 25 days
b) 30 days
c) 27 days
d) 20 days
Answer »Answer: (b)
Using Rule 2,
Let time taken by B in completing the work = x days
Time taken by A = (x - 10) days
⇒ $1/x + 1/{x - 10} = 1/12$
⇒ ${x - 10 + x}/{x(x - 10)} = 1/12$
⇒ $24x - 120 = x^2 - 10x$
⇒ $x^2 - 34x + 120$ = 0
⇒ $x^2 - 30x - 4x + 120$ = 0
⇒ $x (x - 30) - 4 (x - 30)$ = 0
⇒ $(x - 4) (x - 30)$ = 0
⇒ $x = 30$ because $x ≠ 4$
Question : 35 [SSC CHSL 2012]
P is thrice as good a workman as Q and therefore able to finish a job in 48 days less than Q. Working together, they can do it in :
a) 12 days
b) 18 days
c) 24 days
d) 30 days
Answer »Answer: (b)
Using Rule 2,
Let time taken by P = x days
Then, time taken by Q = 3x days
3x - x = 48 ⇒ x = 24
(P + Q)’s 1 day’s work
= $1/24 + 1/72 = {3 + 1}/72 = 1/18$
Required time = 18 days
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Model 6 Efficiency of the worker Shortcuts »
Click to Read...Model 6 Efficiency of the worker Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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