model 7 sold at loss Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

C.P. of article = Rs. x

First S.P. = Rs.${9x}/10$

Case II,

C.P. = ${80x}/100$ = Rs.${4x}/5$

According to the question,

${4x}/5 × 140/100 - {9x}/10$ = 55

${56x}/50 - {9x}/10$ = 55

${56x - 45x}/50$ = 55

11x = 50 × 55

$x = {50 × 55}/11$ = Rs.250

Answer: (d)

CP of the article

= $(100/112 × 2576)$ = Rs.2300

New CP = Rs.2200

Gain per cent

= ${2576 - 2200}/2200 × 100 = 17{1}/11$

Answer: (c)

C.P. of T.V. for Yogita = Rs.x (let)

According to question,

$x × 120/100 × 110/100$ = 33000

$x = {33000 × 100 × 100}/{120 × 110}$ = Rs.25000

Here, $ r_1 = 20%, r_2 = 10%$

C.P. for Deepa = C.P. for yogita

$({1 + r_1}/100)({1 + r_2}/100)$

33000 = C.P. for Yogita

$(1 + 20/100) (1 + 10/100)$

C.P. for Yogita = ${33000 × 100 × 100}/{120 × 110}$ = Rs.25,000

Answer: (d)

Let the CP of the cooker be Rs.x.

Initial SP = ${116x}/100$

Again, SP = $({116x}/100 + 20)$

${116x}/100 + 20 = {120x}/100$

116x + 2000 = 120x

4x = 2000 ⇒ $x = 2000/4$ = Rs.500

Using Rule 11,

Here, x = 16%, R = 20, Y = 20%

C.P. = ${R × 100}/{y - x}$

= ${20 × 100}/{20 - 16}$ = Rs.500

Answer: (b)

Let the CP of the typewriter be Rs.x.

At 5% loss, SP = ${95x}/100$

Now, ${95x}/100 + 80 = {105x}/100$

${105x}/100 - {95x}/100 = 80$

${105x - 95x}/100 = 80$

$x = 8000/10$ = Rs.800

Using Rule 11,

Here, x = 5%, R = 80, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${80 × 100}/{5 + 5}$ = Rs.800