model 7 sold at loss Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

Let the first CP of the commodity be Rs.100.

First SP = Rs.110; Second CP = Rs.90

Gain% = $50/3%$

Second SP = $(100 + 50/3)%$ of 90

= Rs.$(90 × 350/300)$ = Rs.105

Difference of first and second S.P.

= Rs.(110–105) = Rs.5

Since, If the difference is Rs.5, the CP = Rs.100.

Since, If the difference be Rs.2, the

CP = $100/5 × 2$ = Rs.40

Answer: (a)

Let the C.P. of article be Rs.x.

S.P. = ${175x}/200$

New S.P. = Rs.$({7x}/8 + 51.80)$

${175x}/200 + 51.8 = 106/100 × x$

${106x}/100 - {175x}/200 = 51.8$

${212x - 175x}/200 = 51.8$

37 x = 51.8 × 200

$x = {51.8 × 200}/37$ = Rs.280

Using Rule 11,

Here, x = 12.5%, R = Rs.51.80, y = 6%

C.P. = ${R × 100}/{y + x}$

= ${51.80 × 100}/{12.5 + 6}$

= $5180/{18.5}$ = Rs.280

Answer: (d)

Let C.P. of article be Rs.x.

According of the question,

625 - x = x - 545

2 x = 625 + 545 = 1170

x = $1170/2$ = Rs.585

Required S.P. = Rs.(585 + 65) = Rs.650

Answer: (a)

Let the C.P be Rs.x.

First selling price = 90% of x = Rs.${9x}/10$

Second selling price = $({9x}/10 + 10)$

110% of $x = ({9x}/10 + 10)$

${11x}/10 = {9x}/10 + 10 ⇒ {2x}/10 = 10$

$x = {10 × 10}/2 = 50 = Rs.50$

Using Rule 11,

Here, x = 10%, R= 10, y = 10%

C.P. = ${R × 100}/{y + x}$

= ${10 × 100}/{10 + 10}$ = Rs.50

Answer: (b)

Required S.P. of 150 pens.

= 150 × 12 × $115/100$ = Rs.2070

S.P. of first 50 pens

= ${50 × 12 × 110}/100$ = Rs.660

Required S.P. of 100 pens

= 2070 - 660 = Rs.1410

C.P. of 100 pens = Rs.1200

Gain per cent = $210/1200 × 100$

= $35/2 = 17{1}/2%$