model 3 successive discount Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (a)

Using Rule 5,

Single equivalent discount of two successive discounts of 36% and 4%

= 36 + 4 - ${36 × 4}/100$

= 40 - 1.44 = 38.56

Percentage difference

= 40 - 38.56 = 1.44

Required difference

= 500 × ${1.44}/100$ = Rs.7.20

Answer: (c)

Using Rule 5,

Single equivalent discount for two successive discounts of 20% and 10%

= $(20 + 10 - {20 × 10}/100)%$ = 28%

Now , single discount for 28% and 5%

= $(28 + 5 - {28 × 5}/100)%$

= (33 - 1.4) % = 31.6%

Required selling price of bicycle at cash payment

= (100 - 31.6) % of Rs.2000

= ${2000 × 68.4}/100$ = Rs.1368

Answer: (b)

Equivalent discount

= $10 + 5 - {10 × 5}/100 = 14.5%$

CP (for buyer)

= 85.5% of Rs.200000

= Rs.$({85.5 × 200000}/100)$ = Rs.171000

SP = Rs.179550

Gain = Rs.(179550 –171000) = Rs.8550

Gain % = $8550/171000 × 100 =5%$

Using Rule 3,

Here, M.P. = 200000,

S.P. is C.P. byer for $D_1 = 5%, D_2$ = 10%

S.P.= M.P.$({100 - D_1}/100)({100 - D_2}/100)$

= 200000$({100 - 5}/100)({100 - 10}/100)$

= 20 × 95 × 90

C.P. for buyer =171000

S.P. = 179550

Profit =S.P. - $\text"C.P."/\text"C.P" ×100%$

= $8550/171000$ × 100 = 5%

Answer: (c)

Using Rule 5,

Single equivalent discount of two consecutive discount of 30% and 10%

= 30 + 10 - ${30 × 10}/100 = 37%$

Required difference

= 40% of 500 - 37% of 500

= 3% of 500

= $500 × 3/100$ = Rs.15

Answer: (b)

Using Rule 5,

Case I,

Discount = ${30 × 2000}/100$ = Rs.600

Single equivalent discount for discounts of 25% and 5%.

= $(25 + 5 - {25 × 5}/100)$%

= (30 - 1.25)% = 28.75%

Discount = ${28.75 × 2000}/100$ = Rs.575

Difference = Rs.(600 - 575) = Rs.25