model 3 successive discount Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

Case I : A single discount of 30%

Case II : Two successive discounts of 20% and 10% Single equivalent discount

= $(20 + 10 - {20 × 10}/100)$% = 28%

Difference = (30 - 28)% = 2%

Required difference

= 2% of 550

=Rs. ${2 × 550}/100$ = Rs.11.

Answer: (d)

Total discount

= Rs.(920 - 742.90) = Rs.177.10

First discount = 15%

Discount = 15% of 920

= ${920 × 15}/100$ = Rs.138

Price after this discount

= 920 - 138 = Rs.782

Remaining discount

= 177.10 - 138 = Rs.39.10

Let the second discount be x %.

${782 × x}/100 = 39.10$

$x = {39.10 × 100}/782$ = 5%

Using Rule 3,

Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$

$7429000/{920 × 85} = 100 - D_2$

95 = 100 - $D_2 ⇒ D_2$ = 5%

Answer: (b)

Marked price = Rs.720

Actual price = Rs.550.80

First discount = 10%

Let the second discount be x%

Then, we can write

720 (1 - 0.10) (1–0.01x) = 550.80

720 × 0.9 (1– 0.01x) = 550.8

648 (1 - 0.01x) = 550.8

1 - 0.01 x= ${550.8}/648$

0.01 x = $1 - {550.8}/648$

$x = {1 - 0.85}/{0.01}$

x = 0.15 × 100 ⇒ x= 15

Second discount = 15%

Answer: (b)

Equivalent discount of successive discounts of 20% and 10%

= $(20 + 10 - {20 × 10}/100)$% = 28%

Selling Price = (100 - 28) % of Rs.500 = 72 % of 500

= Rs.${500 × 72}/100$ = Rs.360

M.P. = Rs.500, $D_1 = 20%, D_2$ = 10%

S.P.= M.P.$({100 - D_1}/100)({100 - D_2}/100)$

= $500({100 - 20}/100)({100 - 10}/100)$

= $500 × 80/100 × 90/100$ = Rs.360

Answer: (c)

Using Rule 5,

Let the marked price be Rs.x.

In case I, SP = Rs.${70x}/100$

Single discount equivalent to successive discounts of 20% and 10%.

= $(20 + 10 - {20 × 10}/100)$% = 28%

S.P. in this case = ${72x}/100$

${72x}/100 - {70x}/100$ = 72

${2x}/100 = 72$

$x = {72 × 100}/2$ = Rs.3600