model 2 hiking & discounting Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (b)

Let the CP of article be Rs.100.

Marked price = Rs.140

S.P. = ${140 × 80}/100$ = Rs.112

Gain per cent = 12%

Using Rule 8,

Here, r = 40%, $r_1$ = 20%

Required profit or loss %

= ${r × (100 - r_1)}/100 - r_1$

= ${40 × (100 - 20)}/100 - 20$

= ${40 × 80}/100 - 20$

= 32 - 20 = 12% profit

Answer: (c)

Let C.P. be Rs.100.

Marked price = Rs.120

S.P. = ${120 × 95}/100$ = Rs.114

Gain per cent = 14%

Using Rule 8,

Here, r = 20%, $r_1$ = 5%

Gain % = ${r × (100 - r_1)}/100 - r_1$

= ${20 × (100 - 5)}/100 - 5$

= 19 - 5 = 14%

Answer: (a)

Let the cost price be Rs.100.

Marked price = Rs.120

SP = 87$1/2$% of 120

= $175/200 × 120$ = Rs.105

Gain per cent = 5%

Using Rule 8,

Here, r = 20%, $r_1 = 12{1}/2$%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${20 × (100 - {25/2})}/100 - {25/2}$

= ${20 × 175}/200$ - 12.5

= 17.5 - 12.5 = 5%

Answer: (a)

Required loss [As per Rule]

= $({10 × 10}/100)$% = 1%

Here, r = 10% and $r_1$ = 10%

Required profit or loss

= ${r × (100 - r_1)}/100 - r_1$

= ${10 × (100 - 10)}/100 - 10$

= 9 - 10

= –1% (–ve sign shows loss) = 1% loss

Answer: (a)

Let C.P. be 100

Marked price = 110

x% of 110 = 11

x = ${11 × 100}/110$ = 10%

Using Rule 8,

Here, loss % = 1%, r = 10%, $r_1$ = x%

loss % = ${r × (100 - r_1)}/100 - r_1$

–1 = ${100 × (100 - x)}/100 - x$

(–ve sign for loss)

–100 = 1000 - 10x - 100x

+110x = 1100

x = 10% ⇒ r1 =10%