letter or alphabet series Practice Questions Answers Test with Solutions & More Shortcuts
series completion PRACTICE TEST [4 - EXERCISES]
number series
letter or alphabet series
alpha numeric series
continuous pattern series
Directions:
In each of the following questions, various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives.Question : 16 [C.E.T. 2006]
WFB, TGD, QHG, ?
a) NIJ
b) NIK
c) NJK
d) OIK
e) PJK
Answer »Answer: (b)
Question : 17 [Bank P.O. 1999]
UPI, ?, ODP, MBQ, IAW
a) RHJ
b) SHJ
c) SIJ
d) THK
e) TIJ
Answer »Answer: (b)
Question : 18 [S.S.C. 2002]
AYBZC, DWEXF, GUHVI, JSKTL, ?
a) MQORN
b) MQNRO
c) NQMOR
d) QMONR
Answer »Answer: (b)
Question : 19 [I.B.P.S. 2002]
ATTRIBUTION, TTRIBUTIO, RIBUTIO, IBUTI, ?
a) IBU
b) UT
c) UTI
d) BUT
e) None of these
Answer »Answer: (c)
In the first step, one letter from the beginning and one from the end of a term are removed to give the next term.
In the second step, two letters from the beginning of a term are removed.
These two steps are repeated alternately.
Question : 20 [UPSC, 2005]
Consider the following series : ABCD ….. XYZ, YX ….. BA, BCD ….. YZ, YX ….. CBA, BC ….. YZ ….. Which letter occupies the 1000th position in the above series?
a) b
b) c
c) x
d) y
Answer »Answer: (a)
We have 3 patterns :
I. ABCD ….. XYZ, which occurs only once.
II. YX ….. BA, which repeats alternately.
III. BC ….. YZ, which repeats alternately.
Now, I has 26 terms.
So, number of terms before the desired term = (999 - 26) = 973.
Each of the patterns which occurs after
I, has 25 letters. Now, 973 + 25 gives quotient = 38 and remainder = 23.
Thus, the 1000th term of the given series is the 24th term of the 39th pattern after I.
Clearly, the 39th pattern is II and its 24th term is B.
IMPORTANT verbal reasoning EXERCISES
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