find both direction & distance section 2 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 31

Point M is 10 km south of point N. Point O is 10 km east from point N. Point P is in west of point O at a distance of 22km. Point R is 5 km south of point P. what is shortest distance between point R and point N, also point O is which direction respect of point R?

a) $13√2 km,$ north-east

b) 13 km, north-east

c) 13 km, north-west

d) $12√2 km,$ south-east

e) 14 km, south-west

Answer: (b)

Question : 32

An ant moves 10 cm towards east and turns to the right hand moves 3 cm. Then it moves to its right and moved 3 cm. It then turns to his left and moves 2 cm. Finally it turns to his right and travel’s 7 cm. how far and in which direction it is now from the starting point?

a) 5 cm, West

b) 10 cm, East

c) 8 cm, West

d) 9 cm, North

e) None of these

Answer: (a)

Question : 33

A villager went to meet his uncle in another village situated 5 km away in the North-east direction of his own village. From there he came to meet his father-in-law living in a village situated 4 km in the south of his uncle’s village. How far away and in what direction is he now?

a) 4 km in the East

b) 3 km in the North

c) 4 km in the West

d) 3 km in the East

Answer: (d)

The villager moves from his village at O to his uncle’s village at A and thereon to his father-in-law’s village to B.

Clearly, “OBA is right - angled at B.

So, OA2 = OB2 + AB2 ;

OB2 = OA2 – AB2 ;

OB = $√{25 – 16}$ =$√{9}$ = 3 km.

Thus, B is 3 km to the east of his initial position O.

Question : 34

Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point and in which direction?

a) 40 metres East

b) 35 metres East

c) 60 metres East

d) 35 metres North

Answer: (b)

The movements of Rohit are as shown in the figure.

So, Rohit’s distance from starting point A = AE

AE = (AD + DE) = (BC + DE) = (20 + 15) m = 35 m.

Also, E is to the East of A.

direction-and-distance

Question : 35

Sanjeev walks 10 metres towards the south. Turning to the left, he walks 20 metres and then moves to his right. And moving a distance of 20 metres, he turns to the right and walks 20 metres. Finally, he turns to the right and moves a distance of 10 metres. How far and in which direction is he from the starting point?

a) 10 metres South

b) 10 metres North

c) 20 metres North

d) 20 metres South

e) None of these

Answer: (d)

The movements of Sanjeev from A to F are as shown in Figure

Clearly, Sanjeev’s distance from starting point A

= AF = (AB + BF)

= AB + (BE – EF) = AB + (CD – EF)

= [10 + (20 – 10)]m = (10 + 10)m = 20 m.

Also, F lies to the South of A.

So, Sanjeev is 20 metres to the south of his starting point.

direction-and-distance

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