find distance only section 2 Practice Questions Answers Test with Solutions & More Shortcuts
direction & distance sense test PRACTICE TEST [15 - EXERCISES]
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
DIRECTIONS:
Study the informations and answer the question given below:
- Eight friends, A, B, C, D, E, F, G and H are sitting in a square dining table.
- Seven poles A, B, C, D, E, F and G are put in such a way that the distance between the next two decreases by 1 metre.
- The distance between the first two poles, A and B, is 10 metres.
Now answer the following questions.
Question : 1
If the authorities decide to remove one pole and place the remaining on equal distances among the poles, then each set of two poles would be ............. metres apart.
a) 9
b) 8
c) 7
d) 5
e) None of these
Answer »Answer: (a)
After removing the pole the remaining poles are 6 then distance between two poles would be 45 ÷ 5 = 9m .
Question : 2
If a monkey hops from pole G to pole C, then how much distance did it cover ?
a) 22 k
b) 26 km
c) 19 km
d) 25 km
e) None of these
Answer »Answer: (b)
The distance between pole G and C = 8 + 7 + 6 + 5 = 26m
Question : 3
What is the distance between the first pole A and the last pole G ?
a) 45 m
b) 40 m
c) 49 m
d) None of these
e) cannot be determine.
Answer »Answer: (a)
The distance between A and G = (10 + 9 +….+ 5).
Question : 4
Aditya went 15 kms to the west from his house, then turned left and walked 20 kms. He then turned East and walked 25 kms and finally turning left covered 20 kms. How far was he from his house?
a) 10 kms
b) 80 kms
c) 5 kms
d) 40 kms
Answer »Answer: (a)
10 km
Question : 5
Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position?
a) 30 metres
b) 60 metres
c) 20 metres
d) 50 metres
Answer »Answer: (b)
The movements of Gaurav are as shown in Fig.
Clearly, Gaurav's distance from his initial position
P = PX = (PS + SX)
= (QR + SX) = (40 + 20)m = 60.
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