type 1 angle between the hands of clock Practice Questions Answers Test with Solutions & More Shortcuts
clocks PRACTICE TEST [5 - EXERCISES]
type 1 angle between the hands of clock
type 2 position of hands of the clock
type 3 faulty clock
type 4 time gained or lost by clock
type 5 comparing clocks
Question : 6 L.I.C.A.A.O., 2003
At what angle the hands of a clock are inclined at 15 minutes past 5?
a) $\text"58"1°/2$
b) 64°
c) $\text"67"1°/2$
d) $\text"72"1°/2$
Answer »Answer: (c)
Angle traced by hour hand in 21/4 hrs =$ (360/12 × 21/4)^o = 157 1°/2$
Angle traced by min. Hand in 15 min = $(360/12 × 15)^o = 90°$
∴ Required angle = $(157 1°/2) - 90° = 67 1°/2$.
Question : 7
A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is
a) 360°
b) 390°
c) 390.5°
d) None of these
Answer »Answer: (b)
Clearly, the minute hand traverses 65 minutes in 1 hour.
∴ Required angle = $(360/60 × 65)^o = 360°$
Question : 8
Match List I with List II and select the correct answer using the codes given below the lists:
List I (Time) | List II (Angle between hour hand and minute hand of a clock) |
A. 1:10 PM | 20° |
B. 2:15 PM | 22$1/2$° |
C. 8:40 PM | 24° |
25° | |
30° |
a) A-4, B-2, C-1
b) A-4, B-3, C-2
c) A-5, B-2, C-1
d) A-4, B-3, C-2
Answer »Answer: (a)
(A) Angle traced by hour hand in$ 7/6 hrs = (360/12 × 7/6)^o = 35°$
Angle traced by minute hand in $10 min = (360/60 × 10)^o = 60°$
∴ Required angle = (60° - 35°) = 25°
(B) Angle traced by hour hand in $9/4 hrs = (360/12 × 9/4)^o = 67 1°/2$
Angle traced by minute hand in $15 min = (360/60 × 15)^o = 90°$
∴ Required angle = $(90° - 67 1°/2) = 22 1°/2$
(C) Angle traced by hour hand in $26/3 hrs = (360/12 × 26/3)^o = 260°$
Angle traced by minute hand in $40 min = (360/60 × 40)^o$ = 240°
∴ Required angle = (260° - 240°) = 20°
Question : 9
An accurate clock shows 8O' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2O, clock in the afternoon?
a) 144°
b) 150°
c) 168°
d) 180°
Answer »Answer: (d)
Angle traced by the hour hand in $6 hours = (360/12 × 6)^o$ = 180°
Question : 10 [P.C.S., 2006]
The angle between the minute hand and the hour hand of a clock when the time is 4:20, is
a) 0°
b) 10°
c) 5°
d) 20°
Answer »Answer: (b)
Angle traced by hour hand in $13/3 hrs = (360/12 × 13/3)^o= 130°$
Angle traced by min. hand in $20 min = (360/60 × 20)^o = 120°$
∴ Required angle = (130° - 120°) = 10°
IMPORTANT verbal reasoning EXERCISES
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