find a day with reference day Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (c)

4^th Saturday = 22^nd day

3^rd Saturday = 22 - 7 = 15^th day

∴ 13^th day - Saturday - 2 = Thursday

Answer: (b)

Tomorrow = Friday

3 days after tomorrow = 15^th June = Friday + 3 odd days = Monday

Days from 15^th to 30^th June = 15

15 ÷ 7 = 7)15(2 =>remainder 1 odd day

30^th June = Monday + 1 odd day = Tuesday

Answer: (d)

Since Total days from 15^th August, 2011 to 17 September, 2011 = 33

33 ÷ 7 => 7)33(4 = remainder 5 odd days

∴ Required day = Tuesday + 5 odd days

= Sunday

Answer: (c)

Here, 27^th March 1995 was Monday.

Now, for calculating the total number of odd days. first, we calculate the total number of days till 1 November 1994.

∴  Number of days in March, 1995 = 27

Number of days in February 1995 = 28

Number of days in January 1995 = 31

Number of days in December 1994 = 31

Number of days in November 1994 = 29

Total number of days = 146

∴ Number of odd days = $146/7$ = 20$6/7$

So, 6 odd days

∴ On November 1, 1994 = Monday - 6

= Tuesday