find a day with reference day Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

26^th January 2011 to 26th January 2012 will be considered as an ordinary year because 26^th January in 2012 (a leap year) comes before 29^th February.

Hence, the period of this one year will have only 1 odd day.

Since 26^th January 2011 = Wednesday

∴ 26^th January 2012 = Wednesday + 1 odd day

= Thursday

Answer: (b)

As we know that, first and last day of an ordinary year is the same.

Since, 1^st day = Friday

⇒ Last day = Friday

Answer: (b)

Since, December 17, 1899 - Saturday

December 17, 1900 - Sunday

December 18, 1901 - Tuesday

∴ December 22, 1901 - Saturday

Answer: (c)

According to the question,

National day = 4^th Saturday

Since, 1^st day = Tuesday

∴ 1^st Saturday = Tuesday + 4 = 1 + 4 = 5^th day

∴ 2^nd Saturday = 5 + 7 = 12^th day

3^rd Saturday = 12 + 7 = 19^th day

4^th Saturday = 19 + 7 = 26^th day

So, National day was celebrated on 26^th of that month.

Answer: (b)

Number of days in 1996 (366-26) = 340

Number of days in 1997 = 365

Number of days in 1998 = 365

Number of days in 1999 = 365 

Number of days from January 2000 to July 2000 = 31 + 29 + 31 + 30 + 31 + 30 + 31

= 213 

Number of days from 1^st to 15^th August, 2000 = 15

∴ Total days = 340 + 365 + 365 + 365 + 213 + 15 = 1663

∴ 1663 ÷ 7 = remainder 4

∴ 1663 days = (237 X 7 + 4) days = 237 weeks + 4 days

∴  Number of odd days = 4

∴  Day on 15^th August, 2000 = Friday + 4 Odd days = Tuesday