Model 3 Train Vs Bridge/Platform Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CGL Prelim 2000]

The length of a train and that of a platform are equal. If with a speed of 90 km/hr the train crosses the platform in one minute, then the length of the train (in metres) is :

a) 600

b) 750

c) 900

d) 500

Answer: (b)

Using Rule 1,
If a train crosses an electric pole, a sitting/standing man, km or mile stone etc. then distance = Length of train. Then,
Length of train = Speed × Time
And Time = $\text"Length of train"/\text"Speed"$ and
Speed = $\text"Length of train"/\text"Time"$

Let the length of train be x metre Speed = 90 km/hr

= ${90 × 5}/18$ metre /sec. = 25 metre/sec.

Distance covered in 60 sec.

= 25 × 60 = 1500 metres

Now, according to question,

2x = 1500 ⇒ x = 750 metre

Question : 22 [SSC CGL Prelim 2005]

A train, 150 m long, takes 30 seconds to cross a bridge 500 m long. How much time will the train take to cross a platform 370 m long ?

a) 30 secs

b) 24 secs

c) 18 secs

d) 36 secs

Answer: (b)

Using Rule 10,

When a train croses a bridge, distance covered

= length of (bridge + train).

Speed of train = ${150 + 500}/30$

=$650/30 = 65/3$ m/sec.

Time taken to cross the 370m long platform

= ${370 + 150}/{65/3}$

= ${520 × 3}/65$ = 24 seconds

Question : 23 [SSC CPO S.I.2005]

A train takes 18 seconds to pass through a platform 162 m long and 15 seconds to pass through another platform 120 m long. The length of the train (in m) is :

a) 80

b) 90

c) 105

d) 70

Answer: (b)

Using Rule 10,

Let the length of the train be x metres.

When a train corsses a platform it covers a distance equal to the sum of lengths of train and platform.

Also, the speed of train is same.

${x + 162}/18 = {x + 120}/15$

6x + 720 = 5x + 810

6x - 5x = 810 - 720

x = 90

The length of the train = 90m.

Question : 24 [SSC CGL Tier-I 2016]

The lengths of a train and that of a platform are equal. If with a speed of 90 km/hr the train crosses the platform in one minute, then the length of the train (in metres) is

a) 600

b) 750

c) 900

d) 500

Answer: (b)

Let, length of train = length of platform = x metre

Speed of train = 90 kmph

= $({90 × 5}/18)$ m/sec.

= 25 m/sec.

Speed of train

= $\text"Length of train and platform"/ \text"Time taken in crossing"$

25 = ${2x}/60$

2x = 25 × 60

$x = {25 × 60}/2$ = 750 metre

Question : 25 [SSC CAPFs SI 2013]

A train 270 metres long is running at a speed of 36 km per hour, then it will cross a bridge of length 180 metres in :

a) 45 sec

b) 50 sec

c) 35 sec

d) 40 sec

Answer: (a)

Using Rule 10,

36 kmph = $(36 × 5/18)$ m/sec.

= 10 m/sec.

Required time = ${270 + 180}/10$

= 45 seconds

IMPORTANT quantitative aptitude EXERCISES

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