Model 3 Train Vs Bridge/Platform Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CGL Prelim 2005]

A 120 metre long train is running at a speed of 90 km per hour. It will cross a railway platform 230 m long in :

a) 9$1/5$ seconds

b) 7 seconds

c) 14 seconds

d) 4$4/5$ seconds

Answer: (c)

Using Rule 10,

Speed of train = 90 kmph

= $90 × 5/18$ = 25 m/sec

Distance covered

= 230 + 120 = 350 m

Time taken = $350/25$

= 14 seconds

Question : 17 [SSC CGL Prelim 2007]

A train travelling at a speed of 30 m/sec crosses a platform, 600 metres long, in 30 seconds. The length (in metres) of train is

a) 150

b) 200

c) 300

d) 120

Answer: (c)

Using Rule 10,

Let the length of train be x

According to the question,

${x + 600}/30$ = 30

x + 600 = 900

x = 900 - 600 = 300 m

Question : 18 [SSC CPO S.I.2008]

A train with a uniform speed passes a platform, 122 metres long, in 17 seconds and a bridge, 210 metres long, in 25 seconds. The speed of the train is

a) 37.5 km/hour

b) 37.6 km/hour

c) 39.6 km/hour

d) 46.5 km/hour

Answer: (c)

Using Rule 10,

Let the length of the train be x

According to the question,

${x + 122}/17 = {x + 210}/25$

25x + 3050 = 17x + 3570

25x - 17x = 3570 - 3050

8x = 520 ⇒ x = $520/8$ = 65 metres

Speed of the train

= ${65 + 122}/17 = 187/17$ metre/second

= 11 metre/second

= ${11 × 18}/5$ kmph = 39.6 kmph

Question : 19 [SSC CGL Tier-I 2016]

A train, 200 metre long, is running at a speed of 54 km/hr. The time in seconds that will be taken by train to cross a 175 metre long bridge is :

a) 20

b) 25

c) 10

d) 12.5

Answer: (b)

Speed of train = 54 kmph

= $({54 × 5}/18)$ m/sec.

= 15 m/sec.

Required time

= $\text"Length of train and bridge"/ \text" Speed of train"$

= $({200 + 175}/15)$ seconds

= $(375/15)$ seconds = 25 seconds

Question : 20 [SSC SO 2003]

A train is moving at a speed of 132 km/hour. If the length of the train is 110 metres, how long will it take to cross a railway platform 165 metres long?

a) 7.5 seconds

b) 10 seconds

c) 15 seconds

d) 5 seconds

Answer: (a)

When a train crosses a railway platform, it travels a distance equal to sum of length of platform and its own length.

Speed = 132 kmph

= $132 × 5/18 = 110/3$ m/sec.

Required time

= ${110 + 165}/{110/3}$ seconds

= ${275 × 3}/110 = 7.5$ seconds

Using Rule 10,

Here, x = 110m, u = 132 km/hr.

= $132 × 5/18 = 110/3$ m/sec

y = 165m, t = ?

using t = ${x + y}/u$

t = ${110 + 165}/{110/3}$

= ${275 × 3}/110 = {25 × 3}/10$

= $15/2$ = 7.5 sec

IMPORTANT quantitative aptitude EXERCISES

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