Model 5 Split & Fraction of work Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 11 [SSC CGL Tier-II 2015]
A does half as much work as B in three fourth of the time. If together they take 18 days to complete the work, how much time will B alone take to do it ?
a) 45 days
b) 40 days
c) 30 days
d) 50 days
Answer »Answer: (c)
Let the time taken by B in doing the work alone = x days
According to the question,
Time taken by A = $2 × {3x}/4 = {3x}/2$ days
$1/x + 1/{{3x}/2} = 1/18$
$1/x + 2/{3x} = 1/18$
${3 + 2}/{3x} = 1/18$
3x = 18 × 5
$x = {18 × 5}/3$ = 30 days
Question : 12 [SSC CPO SI & ASI 2016]
Dhiru can dig $1/a$ of a field in 20 hours. What fraction of the same field can Kaku dig in 20 hours if the two of them can dig the field in 60 hours, working together at their respective rates ?
a) $1/{3a}$
b) ${(a - 3)}/a$
c) ${(a - 3)}/{3a}$
d) ${3a}/{(a - 3)}$
Answer »Answer: (c)
Dhiru digs $1/a$ part of field in 20 hours.
Dhiru digs 1 part of field in 20a hours.
= $1/60 - 1/{20a} = {a - 3}/{60a}$
Part of field dug by Kaku in 1 hour
= ${20(a - 3)}/{60a} ={a - 3}/{3a}$
Question : 13 [SSC CGL Tier-I 2016]
A can do a certain job in 12 days. B is 60% more efficient than A. Then B can do the same piece of work in
a) 7$1/2$ days
b) 8 days
c) 6 days
d) 6$1/4$ days
Answer »Answer: (a)
A can do a work in 12 days.
B is 60% more efficient than A.
Time taken by B = $(100/160 × 12)$ days
= $15/2 = 7{1}/2$ days
Question : 14 [SSC CGL Prelim 2002]
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then working together what part of the same work they can finish in a day ?
a) $2/5$
b) $1/6$
c) $2/7$
d) $1/9$
Answer »Answer: (b)
Using Rule 2,
A’s 1 day’s work = $1/18$
B’s 1 day’s work = $1/9$
(A + B)’s 1 day’s work
= $1/18 + 1/9 = {1 + 2}/18 = 3/18 = 1/6$
Question : 15 [SSC MTS 2011]
A and B can do a piece of work in 72 days, B and C can do it in 120 days, and A and C can do it in 90 days. When A, B and C work together, how much work is finished by them in 3 days.
a) $1/30$
b) $1/40$
c) $1/10$
d) $1/20$
Answer »Answer: (d)
Using Rule 5If A and B can do a work in 'x' days, B and C can do the same work in 'y' days, C and A can do the same work in 'z' days. Then total time taken, when A, B and C work together =$2/{(1/x + 1/y + 1/z)}$ OR ${2xyz}/{xy + yz + zx}$ days
(A + B)’s 1 day’s work = $1/72$
(B + C)’s 1 day’s work = $1/120$
(C + A)’s 1 day’s work = $1/90$
On adding all three,
2 (A + B + C)’s 1 day’s work
= $1/72 + 1/120 + 1/90 = {5 + 3 + 4}/360 = 1/30$
(A + B + C)’s 1 day’s work = $1/60$
(A + B + C)’s 3 days’ work = $3/60 = 1/20$
IMPORTANT quantitative aptitude EXERCISES
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New 299+ Time and Work Aptitude Test On Individual Wages »
Model 5 Split & Fraction of work Shortcuts »
Click to Read...Model 5 Split & Fraction of work Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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