Model 1 Simplification using VBODMAS Practice Questions Answers Test with Solutions & More Shortcuts
simplification PRACTICE TEST [4 - EXERCISES]
Model 1 Simplification using VBODMAS
Model 2 Simplification based on square & square root
Model 3 Simplification based on cube & cube root
Model 4 Simplification with continued fraction
Question : 6
Find the value of * in the following $1{2/3} ÷ {2/7} × \text"*"/7 = 1{1/4} × 2/3 ÷ {1/6}$
a) 6
b) $1/6$
c) 0.006
d) 0.6
Answer »Answer: (a)
Using Rule 1,
We have
${5/3} ÷ {2/7} × \text"*"/7 = {5/4} × 2/3 × 6$
${5/3} ÷ {2/7} × \text"*"/7 = {5 × 2 × 6}/{4 × 3}$
* = ${5 × 2 × 6 × 3 × 2 × 7}/{5 × 7 × 4 × 3} = 6$
Question : 7 [SSC CGL Prelim 2002]
Find the sum of the following : $1/9 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72$
a) $1/{2520}$
b) $1/2$
c) $1/9$
d) 0
Answer »Answer: (b)
Question : 8
If $50/\text"*" = \text"*"/{12{1/2}}$, then the value of * is :
a) 25
b) $25/2$
c) 4
d) $4/25$
Answer »Answer: (a)
Let the value of * be x.
$50/x = x/{12{1/2}}$
$50/x = {2x}/25$
$2x^2$ = 50 × 25
$x^2$ = 25 × 25 ⇒ x = 25
Question : 9
$9/20 - [1/5 + (1/4 + (5/6 - \ov{1/3 + 1/2}))]$ is equal to
a) $9/10$
b) 0
c) $9/20$
d) 1
Answer »Answer: (b)
Using Rule 1,
$9/20 - [1/5 + (1/4 + (5/6 - \ov{1/3 + 1/2}))]$
= $9/20 - [1/5 + (1/4 + (5/6 - 5/6))]$
= $9/20 - [1/5 +1/4] = 9/20 - 9/20 = 0$
Question : 10 [SSC CGL Prelim 1999]
Evaluate : ${9|3 - 5|- 5|4|÷10}/{- 3 (5) - 2 × 4 ÷ 2}$
a) $4/7$
b) $9/10$
c) – $16/19$
d) – $8/17$
Answer »Answer: (c)
? = ${9|3 - 5|- 5|4|÷10}/{- 3 (5) - 2 × 4 ÷ 2}$
= ${9 × 2 - 5 × 4 ÷ 10}/{- 15 - 8 ÷ 2}$
= ${18 - 2}/{- 19} = -16/19$
IMPORTANT quantitative aptitude EXERCISES
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