Model 1 Simplification using VBODMAS Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21

5 - [4 - {3 - (3 - 3 - 6)}] is equal to :

a) 0

b) 10

c) 4

d) 6

Answer: (b)

Using Rule 1,

An expression must be simplified by following defined order/sequence known as VBODMAS, which is given by:

1st step, V - Vineculum (line brackets)/Bar
  B - Brackets
  O - Of
  D - Division
  M - Multiplication
  A - Addition
Last step, S - Subtraction

There are four types of brackets given below.

  1. – → Line/Bar
  2. ( ) → Simple or Small Bracket/open brackets
  3. { } → Curly Brackets/Braces
  4. [ ] → Square Brackets/Closed brackets

These brackets must be solved in given order only.

? = 5 - [4 - {3 - (3– 3 - 6)}]

= 5 - [4 - { 3 - (– 6)}]

= 5 - [4 - {3 + 6}]

= 5 - [4 - 9]

= 5 + 5 = 10

Question : 22 [SSC CGL Prelim 2005]

The value of $2/3 × 3/{5/6 ÷ {2/3} of 1{1/4}}$ is :

a) $2/3$

b) 2

c) $1/2$

d) 1

Answer: (b)

Using Rule 1,

$2/3 × 3/{5/6 ÷ {2/3} of 1{1/4}}$

$2/3 × 3/{5/6 ÷ {2/3} of {5/4}}$

$2/3 × 3/{{5/6} ÷ {10/12}}$

= $2/3 × 3/{5/6 × 12/10} = 2/3 × 3/1 = 2$

Question : 23

If ${1120}/{√{P}}$ = 80, then P is equal to

a) 225

b) 14

c) 196

d) 140

Answer: (c)

80 × $√{P}$ = 1120

$√{P} = 1120/80 = 14$

P = $(14)^2 = 196$

Question : 24 [SSC CGL Prelim 2003]

Simplify : ${2{3/4}}/{1{5/6}} ÷ {7/8} × (1/3 + 1/4) + 5/7 ÷ {3/4} of {3/7}$

a) 3$2/9$

b) $56/77$

c) $2/3$

d) $49/80$

Answer: (a)

Using Rule 1,

The given expression

${2{3/4}}/{1{5/6}} ÷ {7/8} × (1/3 + 1/4) + 5/7 ÷ {3/4} of {3/7}$

= ${11/4}/{11/6} ÷ {7/8} × ({4+3}/12) + 5/7 ÷ {3/4} of {3/7}$

= $(11/4 × 6/11) ÷ {7/8} × 7/12 + 5/7 ÷ (3/4 × 3/7)$

= ${3/2} ÷ {7/8} × 7/12 + {5/7} ÷ {9/28}$

= ${3/2} × {8/7} × 7/12 + {5/7} ×{28/9}$

= $1 + 20/9 = {9+20}/9 = 29/9 = 3{2}/9$

Question : 25 [SSC CGL Prelim 1999]

1– [5 - {2 + (– 5 + 6 - 2) 2}] is equal to :

a) –2

b) –4

c) 0

d) 2

Answer: (b)

Using Rule 1,

? = 1 - [5 - {2 + (–1)2}]

= 1 - [5 - {2 - 2}]

= 1 - [5 - 0]

= 1 - 5 = - 4

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