Model 1 Simplification using VBODMAS Practice Questions Answers Test with Solutions & More Shortcuts

Question : 26 [SSC CGL Prelim 2003]

The value of 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + 1 ÷ 2)}] is

a) $1/2$

b) 1

c) 2

d) $5/8$

Answer: (d)

Using Rule 1,

= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + 1 ÷ 2)}]

= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + ${1/2}$)}]

= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ ${3/2}$}]

= 1 ÷ [1 + 1 ÷ {1 + ${2/3}$}] = 1 ÷ [1 + 1 ÷ ${5/3}$]

= 1 ÷ [1 + ${3/5}$] = 1 ÷ $8/5 = 5/8$

Question : 27

Simplify : ${{5/3} × {7/51} of {17/5} - {1/3}}/{{2/9 × {5/7} of {28/5} - {2/3}$

a) $1/4$

b) $1/2$

c) 2

d) 4

Answer: (c)

Using Rule 1,

${{5/3} × {7/51} of {17/5} - {1/3}}/{{2/9 × {5/7} of {28/5} - {2/3}$

= ${{5/3} × {7/51} - {1/3}}/{{2/9 × {4} - {2/3}$

= ${7/9 - 1/3}/{8/9 - 2/3} = 4/9 × 9/2 = 2$

Question : 28 [SSC CGL Prelim 2002]

The value of 0.008 × 0.01 × 0.072 ÷ (0.12 × 0.0004) is :

a) 1.02

b) 1.2

c) 0.012

d) 0.12

Answer: (d)

Using Rule 1,

0.008 × 0.01 × 0.072 ÷ (0.12 × 0.0004)

= 0.008 × 0.01 × 0.072 ÷ (0.000048)

= 0.008 × 0.01 × ${0.072}/{0.000048}$

= ${0.00000576}/{0.000048}$ = 0.12

Question : 29 [SSC CGL Prelim 1999]

Evaluate : ${- (4 - 6)^2 - 3(- 2)+|- 6|}/{18 - 9 ÷ 3 × 5}$

a) $7/4$

b) $3/8$

c) $8/3$

d) $4/7$

Answer: (c)

? = ${- (- 2)^2 + 6 +6}/{18 - 15}$

= ${- 4 +12}/3 = 8/3$

Question : 30 [SSC CGL Prelim 2000]

On simplification 3034 - (1002 ÷ 20.04) is equal to

a) 2543

b) 3029

c) 2993

d) 2984

Answer: (d)

Using Rule 1,

3034 - (1002 ÷ 20.04)

= 3034 - $1002/{20 .04}$

= 3034 - $1002/2004 × 100$

= 3034 - 50 = 2984

IMPORTANT quantitative aptitude EXERCISES

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