Model 1 Simplification using VBODMAS Practice Questions Answers Test with Solutions & More Shortcuts
simplification PRACTICE TEST [4 - EXERCISES]
Model 1 Simplification using VBODMAS
Model 2 Simplification based on square & square root
Model 3 Simplification based on cube & cube root
Model 4 Simplification with continued fraction
Question : 26 [SSC CGL Prelim 2003]
The value of 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + 1 ÷ 2)}] is
a) $1/2$
b) 1
c) 2
d) $5/8$
Answer »Answer: (d)
Using Rule 1,
= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + 1 ÷ 2)}]
= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + ${1/2}$)}]
= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ ${3/2}$}]
= 1 ÷ [1 + 1 ÷ {1 + ${2/3}$}] = 1 ÷ [1 + 1 ÷ ${5/3}$]
= 1 ÷ [1 + ${3/5}$] = 1 ÷ $8/5 = 5/8$
Question : 27
Simplify : ${{5/3} × {7/51} of {17/5} - {1/3}}/{{2/9 × {5/7} of {28/5} - {2/3}$
a) $1/4$
b) $1/2$
c) 2
d) 4
Answer »Answer: (c)
Using Rule 1,
${{5/3} × {7/51} of {17/5} - {1/3}}/{{2/9 × {5/7} of {28/5} - {2/3}$
= ${{5/3} × {7/51} - {1/3}}/{{2/9 × {4} - {2/3}$
= ${7/9 - 1/3}/{8/9 - 2/3} = 4/9 × 9/2 = 2$
Question : 28 [SSC CGL Prelim 2002]
The value of 0.008 × 0.01 × 0.072 ÷ (0.12 × 0.0004) is :
a) 1.02
b) 1.2
c) 0.012
d) 0.12
Answer »Answer: (d)
Using Rule 1,
0.008 × 0.01 × 0.072 ÷ (0.12 × 0.0004)
= 0.008 × 0.01 × 0.072 ÷ (0.000048)
= 0.008 × 0.01 × ${0.072}/{0.000048}$
= ${0.00000576}/{0.000048}$ = 0.12
Question : 29 [SSC CGL Prelim 1999]
Evaluate : ${- (4 - 6)^2 - 3(- 2)+|- 6|}/{18 - 9 ÷ 3 × 5}$
a) $7/4$
b) $3/8$
c) $8/3$
d) $4/7$
Answer »Answer: (c)
? = ${- (- 2)^2 + 6 +6}/{18 - 15}$
= ${- 4 +12}/3 = 8/3$
Question : 30 [SSC CGL Prelim 2000]
On simplification 3034 - (1002 ÷ 20.04) is equal to
a) 2543
b) 3029
c) 2993
d) 2984
Answer »Answer: (d)
Using Rule 1,
3034 - (1002 ÷ 20.04)
= 3034 - $1002/{20 .04}$
= 3034 - $1002/2004 × 100$
= 3034 - 50 = 2984
IMPORTANT quantitative aptitude EXERCISES
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