type 4 difference & equality of si rate & years Practice Questions Answers Test with Solutions & More Shortcuts
simple interest PRACTICE TEST [6 - EXERCISES]
type 1 basic simple interest using formula
type 2 increase or decrease in interest rate
type 3 money multiples in ‘n’ years
type 4 difference & equality of si rate & years
type 5 si on ‘n’ years & ‘x/y ‘of sum
type 6 si with ratios
Question : 6 [SSC MTS 2013]
A person deposited Rs.500 for 4 years and Rs.600 for 3 years at the same rate of simple interest in a bank. Altogether he received Rs.190 as interest. The rate of simple interest per annum was
a) 5%
b) 4%
c) 3%
d) 2%
Answer »Answer: (a)
Using Rule 1,
Let 'r' be the rate of interest
190 = ${500 × 4 × r}/100 + {600 × 3 × r}/100$
20r + 18r = 190
38r = 190
r = $190/38$ = 5%
Question : 7 [SSC CGL Prelim 2008]
If Rs.12,000 is divided into two parts such that the simple interest on the first part for 3 years at 12% per annum is equal to the simple interest on the second part for 4$1/2$ years at 16% per annum, the greater part is
a) Rs.6,000
b) Rs.8,000
c) Rs.7,500
d) Rs.7,000
Answer »Answer: (b)
Using Rule 1,
Let the larger part of the sum be x
Smaller part = Rs.(12000 - x)
According to the question,
${x × 3 × 12}/100 = {(12000 - x) × 9 × 16}/{2 × 100}$
36 x = (12000 - x ) 72
x = (12000 - x ) × 2
x + 2x = 24000
3x = 24000
$x = 24000/3$ = Rs.8000
Question : 8 [SSC CGL Prelim 1999]
The simple interest on a certain sum at 5% per annum for 3 years and 4 years differ by Rs.42. The sum is :
a) Rs.280
b) Rs.210
c) Rs.840
d) Rs.750
Answer »Answer: (c)
According to question,
Interest of one year = Rs.42
Rate = 5% and Time = 1 year
Principal = $\text"Interest × 100"/\text"Rate × Time"$
= ${42 × 100}/{5 × 1}$ = Rs.840
Using Rule 13The difference between the S.I. for a certain sum $P_1$ deposited for time $T_1$ at $R_1$ rate of interest and another sum $P_2$ deposited for time $T_2$ at $R_2$ rate of interest isS.I. = ${P_2R_2T_2 - P_1R_1T_1}/100$
$P_1 = P, R_1 = 5%, T_1$ = 3years.
$P_2 = P, R_2 = 5%, T_2$ = 4 years.
S.I.= 42
42 = ${20P - 15P}/100$
P = 42 × 20 = Rs.840
Question : 9 [SSC CHSL 2013]
If x, y, z are three sum of money such that y is the simple interest on x and z is the simple interest on y for the same time and at the same rate of interest, then we have
a) $xyz$ = 1
b) $z^2 = xy$
c) $y^2 = zx$
d) $x^2 = yz$
Answer »Answer: (c)
Using Rule 1,
S.I. = ${P × R × T}/100$
$y = {x × T × R}/100$
and $z = {y × T × R}/100$
So, $y/z = x/y = ⇒ y^2 = zx$
Question : 10 [SSC CHSL 2013]
The simple interest on a sum of money is $1/16$ of the principal and the number of years is equal to the rate per cent per annum. The rate per annum is
a) 2$1/2$%
b) 1$1/2$%
c) 4$1/2$%
d) 3$1/2$%
Answer »Answer: (a)
Let the annual rate of interest = r%
Time = r years
Let the principal be x .
Interest = $x/16$
According to the question,
$x/16 = {x × r × r}/100$ [Since, r = t]
16$r^2$ = 100
$r^2 = 100/16 = 25/4$
r = $√ {25/4} = 5/2 = 2{1}/2$%
Using Rule 5,
Here, n = $1/16$, R = T
RT = n × 100
$R^2 = 100/16$
R = $√{100/16} = 10/4 = 2{1}/2%$
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type 4 difference & equality of si rate & years Shortcuts »
Click to Read...type 4 difference & equality of si rate & years Online Quiz
Click to Start..simple interest Shortcuts and Techniques with Examples
-
type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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