type 4 difference & equality of si rate & years Practice Questions Answers Test with Solutions & More Shortcuts
simple interest PRACTICE TEST [6 - EXERCISES]
type 1 basic simple interest using formula
type 2 increase or decrease in interest rate
type 3 money multiples in ‘n’ years
type 4 difference & equality of si rate & years
type 5 si on ‘n’ years & ‘x/y ‘of sum
type 6 si with ratios
Question : 21 [SSC CGL Prelim 2005]
A sum of Rs.1500 is lent out in two parts in such a way that the simple interest on one part at 10% per annum for 5 years is equal to that on another part at 12.5% per annum for 4 years. The sum lent out at 12.5% is :
a) Rs.1000
b) Rs.500
c) Rs.1250
d) Rs.750
Answer »Answer: (d)
Using Rule 1,
Let the sum lent out at 12.5% be x
Sum lent out at 10% = 1500 - x
Now, ${(1500 - x) × 10 × 5}/100$
= ${x × 12.5 × 4}/100$
50 (1500 - x ) = 50x
2x = 1500
$x = 1500/2$ = Rs.750
Question : 22 [SSC CGL Prelim 2004]
Mohan lent some amount of money at 9% simple interest and an equal amount of money at 10% simple interest each for two years. If his total interest was Rs. 760, what amount was lent in each case ?
a) Rs.1800
b) Rs.1700
c) Rs.2000
d) Rs.1900
Answer »Answer: (c)
Using Rule 1,
Let the sum lent in each case be x.
Then, ${x × 9 × 2}/100 + {x × 10 × 2}/100$ = 760
${x × 2}/100$(9 + 10) = 760
${2 × 19x}/100$ = 760
$x = {760 × 100}/{2 × 19}$ = Rs.2000
Question : 23 [SSC CGL Prelim 2007]
Simple interest on Rs.500 for 4 years at 6.25% per annum is equal to the simple interest on Rs.400 at 5% per annum for a certain period of time. The period of time is
a) 5 years
b) 4 years
c) 8$2/3$ years
d) 6$1/4$ years
Answer »Answer: (d)
Using Rule 1,
Let the period of time be T years. Then,
${400 × 5 × T}/100 = {500 × 4 × 6.25}/100$
T = ${500 × 4 × 6.25}/{400 × 5}$
= $25/4 = 6{1}/4$ years
Question : 24 [SSC CPO S.I.2006]
If the simple interest for 6 years be equal to 30% of the principal, it will be equal to the principal after
a) 30 years
b) 20 years
c) 22 years
d) 10 years
Answer »Answer: (b)
Let the principal be P and rate of interest be r %
According to the question,
${30P}/100 = {P × R × 6}/100$
30 = 6 R
R = 5
Now, let interest be equal to principal in T years.
P = ${P × 5 × T}/100$
T = $100/5$ = 20 years.
Using Rule 5,
Here, n = $30/100 = 3/10$, T = 6 years.
RT = n × 100
R × 6 = $3/10$ × 100
R = 5%
As,S.I. = P
S.I. = ${P × R × T}/100$
100 = RT
100 = 5 × T
This is possible only when T = 20.
Question : 25 [SSC CHSL 2012]
The difference between the simple interest received from two different banks on Rs.500 for 2 years is Rs.2.50. The difference between their (per annum) rate of interest is :
a) 0.25%
b) 0.10%
c) 1.00%
d) 0.50%
Answer »Answer: (a)
${500 × 2 × R_1}/100 - {500 × 2 × R_2}/100$ = 2.5
where $R_1 & R_2$ are rate% of both banks
10 $(R_1 - R_2 )$ = 2.5
$R_1 - R_2 = {2.5}/10$
= 0.25 % per annum
Using Rule 7If the difference between two simple interests is 'x' calculated at different annual rates and times, then principal (P) isP = $ {x × 100}/{(\text"difference in rate") ×(\text"difference in time")}$
Here, P = Rs. 500, x = Rs. 2.50
Difference in time = 2 years.
Difference in rate = ?
500 = ${2.50 × 100}/{(\text"diff.in rate") × 2}$
Different in rate = 0.25%
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type 4 difference & equality of si rate & years Shortcuts »
Click to Read...type 4 difference & equality of si rate & years Online Quiz
Click to Start..simple interest Shortcuts and Techniques with Examples
-
type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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