type 4 difference & equality of si rate & years Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
-
Top 999+ Basic Simple Interest MCQ for BANK SSC UPSC Exam »
-
New 899+ Simple Interest Questions For BANK & IBPS Exams »
-
Top 799+ Simple Interest Aptitude Questions Answers Test »
-
Top 999+ Aptitude Simple Interest MCQ: SSC Practice Test »
-
Top 799+ Simple Interest Question and Answer Test for SSC »
-
New 750+ Simple Interest MCQ with Ratios For All BANK SSC »
The following question based on simple interest topic of quantitative aptitude
(a) 2$1/2$%
(b) 1$1/2$%
(c) 4$1/2$%
(d) 3$1/2$%
The correct answers to the above question in:
Answer: (a)
Let the annual rate of interest = r%
Time = r years
Let the principal be x .
Interest = $x/16$
According to the question,
$x/16 = {x × r × r}/100$ [Since, r = t]
16$r^2$ = 100
$r^2 = 100/16 = 25/4$
r = $√ {25/4} = 5/2 = 2{1}/2$%
Using Rule 5,
Here, n = $1/16$, R = T
RT = n × 100
$R^2 = 100/16$
R = $√{100/16} = 10/4 = 2{1}/2%$
Discuss Form
Read more difference equality in si rate years Based Quantitative Aptitude Questions and Answers
Question : 1
The simple interest on Rs.4,000 in 3 years at the rate of x% per annum equals the simple interest on Rs.5,000 at the rate of 12% per annum in 2 years. The value of x is
a) 6%
b) 10%
c) 9%
d) 8%
Answer »Answer: (b)
Using Rule 1,
S.I. = ${\text"Principal × Rate × Time"/100$
${4000 × 3 × x}/100$
= ${5000 × 2 × 12}/100$
$x = {5 × 2 × 12}/{4 × 3}$
= 10% per annum
Question : 2
A borrows Rs.800 at the rate of 12% per annum simple interest and B borrows Rs.910 at the rate of 10% per annum, simple interest. In how many years will their amounts of debt be equal ?
a) 20 years
b) 18 years
c) 24 years
d) 22 years
Answer »Answer: (d)
Using Rule 1,
Let the period of time be T years.
800 + ${800 × 12 × T}/100$
= 910 + ${910 × 10 × T}/100$
800 + 96 T = 910 + 91T
96 T - 91 T = 910 - 800
5T = 110
T = $110/5$ = 22 years.
Question : 3
The simple interest on a certain sum for 8 months at 4% per annum is Rs.129 less than the simple interest on the same sum for 15 months at 5% per annum. The sum is :
a) Rs.2400
b) Rs.2,580
c) Rs.3600
d) Rs.2529
Answer »Answer: (c)
Let the sum be x
${x × 5 × 15}/{100 × 12} - {x × 4 × 8}/{100 × 12}$ = 129
$x/{100 × 12}$(75 - 32) = 129
$x = {129 × 1200}/43$ = Rs.3600
Using Rule 13,
$P_1 = P, R_1 = 4%$
$T_1 = 8 months = 8/12$ years
$P_2 = P, R_2$ = 5%
$T_2 = 15 month = 15/12$ years
S.I. = Rs.129
129 = ${P × 5 × 15/12 - P × {4 × 8}/12}/100$
12900 = ${75P - 32P}/12$
12900 = ${43P}/12$
P = Rs.3600
Question : 4
If x, y, z are three sum of money such that y is the simple interest on x and z is the simple interest on y for the same time and at the same rate of interest, then we have
a) $xyz$ = 1
b) $z^2 = xy$
c) $y^2 = zx$
d) $x^2 = yz$
Answer »Answer: (c)
Using Rule 1,
S.I. = ${P × R × T}/100$
$y = {x × T × R}/100$
and $z = {y × T × R}/100$
So, $y/z = x/y = ⇒ y^2 = zx$
Question : 5
The simple interest on a certain sum at 5% per annum for 3 years and 4 years differ by Rs.42. The sum is :
a) Rs.280
b) Rs.210
c) Rs.840
d) Rs.750
Answer »Answer: (c)
According to question,
Interest of one year = Rs.42
Rate = 5% and Time = 1 year
Principal = $\text"Interest × 100"/\text"Rate × Time"$
= ${42 × 100}/{5 × 1}$ = Rs.840
Using Rule 13The difference between the S.I. for a certain sum $P_1$ deposited for time $T_1$ at $R_1$ rate of interest and another sum $P_2$ deposited for time $T_2$ at $R_2$ rate of interest isS.I. = ${P_2R_2T_2 - P_1R_1T_1}/100$
$P_1 = P, R_1 = 5%, T_1$ = 3years.
$P_2 = P, R_2 = 5%, T_2$ = 4 years.
S.I.= 42
42 = ${20P - 15P}/100$
P = 42 × 20 = Rs.840
Question : 6
If Rs.12,000 is divided into two parts such that the simple interest on the first part for 3 years at 12% per annum is equal to the simple interest on the second part for 4$1/2$ years at 16% per annum, the greater part is
a) Rs.6,000
b) Rs.8,000
c) Rs.7,500
d) Rs.7,000
Answer »Answer: (b)
Using Rule 1,
Let the larger part of the sum be x
Smaller part = Rs.(12000 - x)
According to the question,
${x × 3 × 12}/100 = {(12000 - x) × 9 × 16}/{2 × 100}$
36 x = (12000 - x ) 72
x = (12000 - x ) × 2
x + 2x = 24000
3x = 24000
$x = 24000/3$ = Rs.8000
simple interest Shortcuts and Techniques with Examples
-
type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
Verbal Reasoning
Question & Answer Quiz
Non Verbal Reasoning
Question & Answer Quiz
Quantitative Aptitude
Question & Answer Quiz
Computer MCQ
Question & Answer Quiz
General English
Question & Answer Quiz
History GK
Question & Answer Quiz
Polity GK
Question & Answer Quiz
Geography GK
Question & Answer Quiz
Economy GK
Question & Answer Quiz
General Awareness GK
Question & Answer Quiz
Recently Added Subject & Categories For All Competitive Exams
Most Important Antonyms Vocabulary - IBPS Clerk Prelims 2024
Latest Antonyms multiple choice questions and answers with free PDFfor IBPS Clerk Prelims 2024. English Vocabulary practice exercise for all bank exam
Continue Reading »
Syllogism Practice Questions Answers PDF - IBPS Clerk 2024
Practice Verbal Reasoning Syllogism multiple choice questions and answers with Fully solved explanation, PDF for the IBPS Clerk Prelims 2024 Bank Exam
Continue Reading »
IBPS Clerk Prelims 2024 Synonyms Questions Solved Answers
Most important IBPS Clerk Prelims 2024 Synonyms and Antonyms multiple choice questions and answers with detailed solutions, English vocabulary PDF Download
Continue Reading »
New Cloze Test Questions and Answers PDF - IBPS Clerk 2024
The most important Cloze Test questions with detailed answers for upcoming IBPS Clerk prelims 2024. Latest English verbal ability practice MCQs, PDF
Continue Reading »