Probability Model Questions Set 1 Practice Questions Answers Test With Solutions & More Shortcuts
PROBABILITY PRACTICE TEST [1  EXERCISES]
Probability Model Questions Set 1
Question : 1
Two packs of cards are thoroughly mixed and shuffled and two cards are drawn at random, one after the other. What is the probability that both of them are jacks?
a) $2/13$
b) $1/169$
c) $1/13$
d) $7/1339$
e) $1/179$
Answer »Answer: (d)
Total number of cards = 104 = 2 × 52
and total number of jacks = 8 = 2 × 4
∴ Probability for the jack in first draw = $8/{104}$
and probability for the jack in second draw = $7/{103}$
Since both the events are independent events.
Hence the probability that both of them are jacks.
= ${8}/{104}$ × ${7}/{103}$ = $7/{1339}$
Question : 2
A basket contains three blue and four red balls. If three balls are drawn at random from the basket, what is the probability that all the three are either blue or red ?
a) $1/7$
b) $3/28$
c) 1
d) $3/14$
e) None of these
Answer »Answer: (e)
Probability to be a Blue = ${^3C_3}/{^7C_3}$
Probability to be a Red = ${^4 C_3}/{^7C_3}$
Required probability = ${^3 C_3}/{^7 C_3}$ + ${^4 C_3}/{^7C_3}$ = $2/{35}$
Question : 3
In a box carrying one dozen of oranges, onethird have become bad. If 3 oranges are taken out from the box at random, what is the probability that at least one orange out of the three oranges picked up is good?
a) $54/55$
b) $3/55$
c) $1/55$
d) $45/55$
e) None of these
Answer »Answer: (a)
P(At least one good) = 1 – P(All bad)
= 1  ${{^4C_3}/{^12C_3}}$ = 1  ${4/{220}}$ = 1 ${1/{55}}$= ${54}/{55}$
Question : 4
Directions :
Study the given information carefully and answer the questions that follow.
A basket contains 4 red, 5 blue and 3 green marbles.
If two marbles are drawn at random, what is the probability that both are red ?
a) $1/2$
b) $1/6$
c) $3/7$
d) $2/11$
e) None of these
Answer »Answer: (e)
Total possible result n(S) = $^{12}C_{2}$ = ${12 × 11}/{1 × 2}$ = 66
Total number of event = n(E) $^4 C _2$ = ${4 × 3}/{1 × 2}$ = 6
∴ Required probability = ${n(E)}/{n(S)}$ = $6/{66}$ = $1/{11}$
Question : 5
A dice is thrown. What is the probability that the number shown on the dice is not divisible by 3?
a) $2/3$
b) $2/5$
c) $1/3$
d) $1/4$
e) None of these
Answer »Answer: (a)
S = {1, 2, 3, 4, 5, 6}; n(S) = 6
E(not divisible by 3) = 1, 2, 4, 5}, n(E) = 4
∴ P(not divisible by 3) = $4/6$ = $2/3$
IMPORTANT QUANTITATIVE APTITUDE EXERCISES
Probability Model Questions Set 1 Online Quiz
Click to Start..QUANTITATIVE APTITUDE CATEGORIES

» Number System

» Average

» LCM & HCF

» Percentage

» Profit & Loss

» Time & Work

» Pipes & Cisterns

» Time & Distance

» Trains

» Compound Interest

» Simplification

» Discount

» Power

» Permutations & Combination

» Ratio & Proportion

» Advance Math

» Algebraic Expressions

» Trigonometric Ratios & Identities

» Simple Interest

» Alligation & Mixtures

» Boats & Streams

» Set Theory

» Linear Equations

» Quadratic Equations

» Mensuration

» Squareroots & Cuberoots

» Data Sufficiency

» Logarithm

» Probability

» Statistics
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