type 2 selection grouping & team formation on condition puzzles Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (b)

The advocates are A, B and R; doctors are C, D, P, Q, s; teachers are E, T and U. The team consists of three teachers i.e. E, T, U. Now, A, P and U have to be together. E and Q have to be together.

Thus, the team is A, E, P, Q, T, U.

Answer: (a)

The male advocates are A and B; male doctors are C and D; lady doctors are P, Q and S; teachers are E, T and U. If A is selected, P and U will be selected. D and P cannot go together.

So, a male doctor C will be selected C and T have to be together. Thus, the team is A, C, P, T, U. If B is selected, D will not be selected. So, male doctor C will be chosen. C and T have to be together.

Now, the second teacher to be selected is E or U. But, U cannot go without A. So, E will be selected. E and Q have to be together.

Thus, the team can also be B, C, E, Q, T.

Answer: (c)

The advocates are A, B and R; the doctors are C, D, P, Q and S; male teacher is E. Clearly, E will be selected. E and Q have to be together. C and Q cannot be together.

So, C will not be selected. P also cannot be selected because U is not selected. So, two other doctors D and S will be selected. P is not selected, so A will not be selected. D is selected, so B cannot be selected.

Thus, the team is D, E, Q, R, S.

Answer: (a)

A, C, P, R, T, U and A, E, P, Q, R, T are wrong because each of these combinations consists of our ladies.

B, C, E, Q, R, T is incorrect because B and R cannot go together.

Answer: (d)

If A is on the team, Y and B cannot be selected. So, the two senior executives in the team must be X and Z. Since Z and C cannot be taken together,

so the fourth member must be D.