Arithmetical Reasoning section 2 MCQ Practice Questions Answers Test with Solutions & More Shortcuts
Arithmetical Reasoning PRACTICE TEST [2 - EXERCISES]
Arithmetical Reasoning section 1 MCQ
Arithmetical Reasoning section 2 MCQ
Question : 11
There are 3 societies A, B, C having some tractors each. A gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. After some days C gives A and B as many tractors as they have. Finally each has 24 tractors. What is the original No. of tractors each had in the beginning?
a) A-21, B-12, C-29
b) A-29, B-21, C-12
c) A-39, B-21, C-12
d) A-21, B-12, C-39
Answer »Answer: (c)
According to the question, A gives B as many tractors that they already have
Number of tractors with A is greater than number of tractors with B and C. Only option (c) fulfill the statement.
Question : 12
The letters L, M, N, O, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N?
a) 4
b) 7
c) 5
d) 6
Answer »Answer: (d)
6 | 4 | 9 | ||||||
L | M | N | O | P | Q | R | S | T |
difference between P & T is 5 i.e., T = 5 + 4 = 9
difference between N & T is 3 i.e., N = 9 – 3 = 6
So, integer assigned to N = 6
Question : 13
A fibres 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed
a) 72 birds
b) 30 birds
c) 60 birds
d) 90 birds
Answer »Answer: (b)
Let the total number of shots be x. then,
Shots fired by A = $5/8$ x ; Shots fired by B = $3/8$ x
Killing shots by A = $1/3$ of $5/8 x = {5x}/{24}$ ;
Shots missed by B = $1/2$ of $3/8 x = {3x}/{16}$ .
∴ ${3x}/{16}$ = 27 or x = $({27 × 16}/3)$ = 144
Birds killed by A = ${5x}/{24} = (5/{24} × 144)$ = 30
Question : 14
In three coloured boxes - red, green and blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
a) 45
b) 18
c) 36
d) None of these
Answer »Answer: (d)
Let R, G and B represent the number of balls in red, green and blue boxes respectively.
Then, R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2 × 2R = 4R or G = 3R. Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 6R = 108 R = 18.
Therefore number of balls in green box = G = 3R = (3 × 18) = 54.
Question : 15
If every 2 out of 3 ready made shirts need alterations in the sleeves, and every 4 out of 5 need it in the body, how many alterations will be required for 60 shirts?
a) 133
b) 88
c) 123
d) 143
Answer »Answer: (a)
Number of alterations required in 1 shirt
= $(2/3 + 3/4 + 4/5) = {133}/{60}$
∴ Number of alterations required in 60 shirts
= $({133}/{60} × 60)$ = 133
IMPORTANT verbal reasoning EXERCISES
Arithmetical Reasoning section 2 MCQ Online Quiz
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