Model 5 Train Vs Both platform and a man/a pole Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11 [SSC CGL Tier-I 2016]

A train 110 metre long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ?

a) 6 seconds

b) 7 seconds

c) 10 seconds

d) 5 seconds

Answer: (a)

Relative speed of train

= (60 + 6) kmph.

=$({66 × 5}/18)$ m/sec.

= $55/3$ m/sec.

Length of train = 110 metre

∴ Required time = $(110/{55/3})$ seconds

= $({110 × 3}/55)$ seconds = 6 seconds

Question : 12 [SSC CPO S.I.2004]

A person standing on a railway platform noticed that a train took 21 seconds to completely pass through the platform which was 84 m long and it took 9 seconds in passing him. The speed of the train was

a) 32.4 km/hour

b) 50.4 km/hour

c) 75.6 km/hour

d) 25.2 km/hour

Answer: (d)

Rule 10 and Rule 1,

Let the length of train be x metres.

When the train crosses the standing man, its speed = $x/9$

When the train crosses the platform of length 84 m, its speed = ${x + 84}/21$

Obviously, $x/9 = {x + 84}/21$

21x - 9x = 9 × 84

12x = 9 × 84

$x = {9 × 84}/12$ = 63 m

Required speed

= $63/9$ m/sec = $63/9 × 18/5$ kmph

= 25.2 kmph

Question : 13 [SSC CGL Tier-I 2013]

A train moving at a rate of 36 km/hr. crosses a standing man in 10 seconds. It will cross a platform 55 metres long, in :

a) 7 seconds

b) 15$1/2$ seconds

c) 5$1/2$ seconds

d) 6 seconds

Answer: (b)

Rule 10 and Rule 1,

Speed of train = 36 kmph

= $36 × 5/18$ = 10 m/sec

Length of train

= 10 × 10 = 100 metres

Required time = ${100 + 55}/10$

= 15$5/10 = 15{1}/2$ second

= 15.5 seconds

Question : 14 [SSC CGL Prelim 2004]

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?

a) 70 km/hr

b) 79 km/hr

c) 79.2 km/hr

d) 69.5 km/hr

Answer: (c)

Rule 10 and Rule 1,

Let the length of train be x metres.

Then, speed of train when it passes a telegraph post

= $x/8$ m/sec. and speed of train, when it passes the bridge = ${x + 264}/20$

Clearly, $x/8 = {x + 264}/20$

$x/2 = {x +264}/5$

5x = 2x + 528

3x = 528 ⇒ $x = 528/3$ = 176m

Speed of train

= $176/8$ = 22 m/sec.

= 22 × $18/5$ Kmph = 79.2 kmph

Question : 15 [SSC CPO S.I.2007]

A train passes a platform 90 metre long in 30 seconds and a man standing on the platform in 15 seconds. The speed of the train is :

a) 14.6 kmph

b) 18.4 kmph

c) 21.6 kmph

d) 12.4 kmph

Answer: (c)

Rule 10 and Rule 1,

Let the length of the train be x

According to the question,

Speed of the train

= ${x + 90}/30 = 15$

x + 90 = 2x ⇒ x = 90 m

Speed of train = $90/15$

= 6 m/s = $6 × 18/5$ kmph

= 21.6 kmph

IMPORTANT quantitative aptitude EXERCISES

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