Model 6 Change in speed Vs Change with time travel Practice Questions Answers Test with Solutions & More Shortcuts
trains PRACTICE TEST [6 - EXERCISES]
Model 1 Train Vs Train in same direction
Model 2 Train Vs Train in opposite direction
Model 3 Train Vs Bridge/Platform
Model 4 Train Vs Pole/Signal Post/Man
Model 5 Train Vs Both platform and a man/a pole
Model 6 Change in speed Vs Change with time travel
Question : 16 [SSC CGL Prelim 2007]
A student walks from his house at a speed of 2$1/2$ km per hour and reaches his school 6 minutes late. The next day he increases his speed by 1 km per hour and reaches 6 minutes before school time. How far is the school from his house ?
a) $7/4$ km
b) $9/4$ km
c) $11/4$ km
d) $5/4$ km
Answer »Answer: (a)
Let the required distance be x km.
Difference of time
= 6 + 6 = 12 minutes = $1/5$ hr.
According to the question,
$x/{5/2} - x/{7/2} = 1/5$
${2x}/5 - {2x}/7 = 1/5$
${14x - 10x}/35 = 1/5$
${4x}/35 = 1/5 ⇒ x = 35/20 = 7/4$ km.
Using Rule 10,
Here, $S_1 = 2{1}/2 , t_1 = 6, S_2 = 3{1}/2 , t_2$ = 6
Distance = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
= ${5/2 × 7/2 × (6 + 6)}/{7/2 - 5/2}$
= $35/4 × 12/60 = 7/4$ km
Question : 17 [SSC CPO S.I.2009]
A boy is late by 9 minutes if he walks to school at a speed of 4 km/hour. If he walks at the rate of 5 km/hour, he arrives 9 minutes early. The distance to his school is
a) 5 km
b) 4 km
c) 6 km
d) 9 km
Answer »Answer: (c)
Let the required distance be x km.
According to the question,
$x/4 - x/5 = 18/60$
${5x - 4x}/20 = 3/10$
$x = 3/10 × 20$ = 6 km
Using Rule 10,
Here, $S_1 = 4, t_1 = 9, S_2 = 5, t_2$ = 9
Distance = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
= ${(4 × 5)(9 + 9)}/{5 - 4}$
= $20 × 18/60 = $6 km
Question : 18 [SSC CGL Tier-I 2014]
A train travelling at a speed of 55 km/hr travels from place X to place Y in 4 hours. If its speed is increased by 5 km/hr., then the time of journey is reduced by
a) 35 minutes
b) 20 minutes
c) 30 minutes
d) 25 minutes
Answer »Answer: (b)
Using Rule 1
Distance between stations X and Y
= Speed × Time = 55 × 4 = 220 km.
New speed = 55 + 5 = 60 kmph
Required time = $220/60$
= $11/3$ hours
= 3 hours 40 minutes.
Required answer
= 4 hours - 3 hours 40 minutes
= 20 minutes
IMPORTANT quantitative aptitude EXERCISES
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Top 399+ Trains Based Time and Distance MCQs For BANK SSC »
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New 500+ Aptitude Problems on Train For All BANK SSC Exam »
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Top 499+ Aptitude MCQs on Trains Crossing Bridge/Platform »
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New 500+ Aptitude MCQs on Train Crossing Pole/Post or Man »
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Top 499+ Trains Problems Using Time and Distance For SSC »
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Top 489+ Time And Distance MCQ Problems on Train For BANK »
Model 6 Change in speed Vs Change with time travel Shortcuts »
Click to Read...Model 6 Change in speed Vs Change with time travel Online Quiz
Click to Start..trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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