Model 6 Change in speed Vs Change with time travel Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 5 km
(b) 4 km
(c) 6 km
(d) 9 km
The correct answers to the above question in:
Answer: (c)
Let the required distance be x km.
According to the question,
$x/4 - x/5 = 18/60$
${5x - 4x}/20 = 3/10$
$x = 3/10 × 20$ = 6 km
Using Rule 10,
Here, $S_1 = 4, t_1 = 9, S_2 = 5, t_2$ = 9
Distance = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
= ${(4 × 5)(9 + 9)}/{5 - 4}$
= $20 × 18/60 = $6 km
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Read more changing speed with time travel Based Quantitative Aptitude Questions and Answers
Question : 1
A train travelling at a speed of 55 km/hr travels from place X to place Y in 4 hours. If its speed is increased by 5 km/hr., then the time of journey is reduced by
a) 35 minutes
b) 20 minutes
c) 30 minutes
d) 25 minutes
Answer »Answer: (b)
Using Rule 1
Distance between stations X and Y
= Speed × Time = 55 × 4 = 220 km.
New speed = 55 + 5 = 60 kmph
Required time = $220/60$
= $11/3$ hours
= 3 hours 40 minutes.
Required answer
= 4 hours - 3 hours 40 minutes
= 20 minutes
Question : 2
A student walks from his house at a speed of 2$1/2$ km per hour and reaches his school 6 minutes late. The next day he increases his speed by 1 km per hour and reaches 6 minutes before school time. How far is the school from his house ?
a) $7/4$ km
b) $9/4$ km
c) $11/4$ km
d) $5/4$ km
Answer »Answer: (a)
Let the required distance be x km.
Difference of time
= 6 + 6 = 12 minutes = $1/5$ hr.
According to the question,
$x/{5/2} - x/{7/2} = 1/5$
${2x}/5 - {2x}/7 = 1/5$
${14x - 10x}/35 = 1/5$
${4x}/35 = 1/5 ⇒ x = 35/20 = 7/4$ km.
Using Rule 10,
Here, $S_1 = 2{1}/2 , t_1 = 6, S_2 = 3{1}/2 , t_2$ = 6
Distance = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
= ${5/2 × 7/2 × (6 + 6)}/{7/2 - 5/2}$
= $35/4 × 12/60 = 7/4$ km
Question : 3
If a man reduces his speed to 2/ 3, he takes 1 hour more in walking a certain distance. The time (in hours) to cover the distance with his normal speed is :
a) 1
b) 3
c) 1.5
d) 2
Answer »Answer: (d)
Since man walks at $2/3$ of usual speed, time taken wil be $3/2$ of usual time.
$3/2$ of usual time
= usual time + 1 hour.
$(3/2 –1)$ of usual time = 1
usual time = 2 hours.
Question : 4
If a man walks 20 km at 5 km/ hr, he will be late by 40 minutes. If he walks at 8 km/hr, how early from the fixed time will he reach?
a) 25 minutes
b) 50 minutes
c) 1$1/2$ hours
d) 15 minutes
Answer »Answer: (b)
Time taken to cover 20 km at the speed of 5km/hr
= 4 hours.
Fixed time = 4 hours - 40 minutes
= 3 hour 20 minutes
Time taken to cover 20 km at the speed of 8 km/hr
= $20/8$ = 2 hours 30 minutes
Required time
= 3 hours 20 minutes - 2 hours 30 minutes
= 50 minutes
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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