Model 4 Working with Man, Woman, Child Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 31 [SSC CGL Prelim 2004]
6 men or 12 women can do a piece of work in 20 days. In how many days can 8 men and 16 women do twice as big as this work ?
a) 15 days
b) 2 days
c) 5 days
d) 10 days
Answer »Answer: (a)
6 men = 12 women ⇒ 1 man = 2 women
Now, 8 men + 16 women
= (8 × 2 + 16) women = 32 women
12 women can do a work in 20 days.
1 woman can do the work in 20 × 12 days.
32 women can do the twice work in = ${20 × 12 × 2}/32$ = 15 days.
Using Rule 12,
Here, A = 6, B= 12, a = 20, $A_1$ = 8, $B_1$ = 16
Time taken = ${a(A × B)}/{A_1B + B_1A}$
= ${20(6 × 12)}/{8 × 12 + 16 × 6}$
= ${20 × 72}/192 = 15/2$
They will do the twice as big work in $2 × 15/2$ days = 15 days
Question : 32 [SSC CGL Prelim 2000]
If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work?
a) 3 days
b) 4 days
c) 5 days
d) 2 days
Answer »Answer: (a)
3m = 6w ⇒ 1m = 2w
12m + 8w = (12 × 2w) + 8w = 32w
6 women can do the work in 16 days.
32 women can do the work in ${16 × 6}/32 = 3$ days
Using Rule 12If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work inTime taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days
Here, A = 3, B = 6, a = 16, $A_1$ = 12, $B_1$ = 8
Time taken = ${a(A × B)}/{A_1B + B_1A}$
= ${16(3 × 6)}/{12 × 6 + 8 × 3}$
= ${16 × 18}/96$ = 3 days
Question : 33 [SSC CGL Tier-I 2016]
12 men and 16 boys can do a piece of work in 5 days; 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is
a) 1 : 3
b) 2 : 1
c) 3 : 1
d) 5 : 4
Answer »Answer: (b)
Work done by 12 men + 16 boys in 5 days
≡ Work done 13 men + 24 boys in 4 days
(60 men + 80 boys)’s 1 day’s work ≡ (52 men + 96 boys)’s 1 day’s work
(60 - 52) men ≡ (96 - 80) boys
8 men ≡ 16 boys ⇒ 1 man ≡ 2 boys
∴ Required ratio = 2 : 1
Question : 34 [SSC CGL Prelim 2005]
A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman alone take to complete the work?
a) 24 days
b) 9 days
c) 21 days
d) 27 days
Answer »Answer: (b)
Work done by 1 woman in 1 day
= $1/3 - 1/6 - 1/18 = {6 - 3 - 1}/18 = 1/9$
Woman will do the work in 9 days.
Using Rule 18A, B and C can do a certain work together within 'x' days. While, any two of them can do the same work separately in 'y' and 'z' days, then in how many days can 3rd do the same work?Required time = ${xyz}/{yz - x(y + z)}$days
Here, x = 3, y = 6 and z = 18
Required time = ${xyz}/{yz - x(y + z)}$ days
= ${3 × 6 × 18}/{6 × 18 - 3(6 + 18)}$
= $324/{108 - 3 24}$
= $324/{108 - 3 × 24} = 324/36$ = 9
Question : 35 [SSC CHSL 2013]
Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work ?
a) 3 days
b) 1 days
c) 2 days
d) 4 days
Answer »Answer: (c)
Work done in two days = $1/6 × 2$
= $1/3$, remaining work = $2/3$
${M_1D_1}/W_1 = {M_2D_2}/W_2$
${3 × 2}/{1/3} = {6 × D_2}/{2/3}$
$D_2 = {3 × 2 × 2}/6$ = 2 days
Using Rule 10If food is available for 'a' days for 'A' men at a certain place and after 'b' days. 'B' men join, then the remaining food will serve total men forRequired time = ${A(a - b)}/{(A + B)}$ daysIf food is available for 'a' days for 'A' men at a certain place, and after 'b' days 'B' men leave then the remaining food will serve remaining men forRequired time = ${A(a - b)}/{(A - B)}$ days
Here, A = 3, a = 6, b = 2, B = 3
Required time = ${A(a - b)}/{(A + B)}$
= ${3(6 - 2)}/{3 + 3}$
= ${3 × 4}/6$ = 2 days
IMPORTANT quantitative aptitude EXERCISES
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Top 199+ Basic Time and Work Aptitude MCQs with Answers »
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Top 200+ Time and Work Problem Solving By Formula Method »
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New 189+ Time & Work MCQs Practice Test for BANK Exams »
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Top 199+ Time & Work MCQs: Men Women Child for BANK Exam »
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Top 199+ Time and Work Questions Test on Fraction of Work »
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Top 199+ Time and Work Efficiency Based Aptitude MCQ Quiz »
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New 299+ Time and Work Aptitude Test On Individual Wages »
Model 4 Working with Man, Woman, Child Shortcuts »
Click to Read...Model 4 Working with Man, Woman, Child Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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