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The following question based on time & work topic of quantitative aptitude
(a) 15 days
(b) 2 days
(c) 5 days
(d) 10 days
The correct answers to the above question in:
Answer: (a)
6 men = 12 women ⇒ 1 man = 2 women
Now, 8 men + 16 women
= (8 × 2 + 16) women = 32 women
12 women can do a work in 20 days.
1 woman can do the work in 20 × 12 days.
32 women can do the twice work in = ${20 × 12 × 2}/32$ = 15 days.
Using Rule 12,
Here, A = 6, B= 12, a = 20, $A_1$ = 8, $B_1$ = 16
Time taken = ${a(A × B)}/{A_1B + B_1A}$
= ${20(6 × 12)}/{8 × 12 + 16 × 6}$
= ${20 × 72}/192 = 15/2$
They will do the twice as big work in $2 × 15/2$ days = 15 days
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Read more working with man woman child Based Quantitative Aptitude Questions and Answers
Question : 1
If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work?
a) 3 days
b) 4 days
c) 5 days
d) 2 days
Answer »Answer: (a)
3m = 6w ⇒ 1m = 2w
12m + 8w = (12 × 2w) + 8w = 32w
6 women can do the work in 16 days.
32 women can do the work in ${16 × 6}/32 = 3$ days
Using Rule 12If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work inTime taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days
Here, A = 3, B = 6, a = 16, $A_1$ = 12, $B_1$ = 8
Time taken = ${a(A × B)}/{A_1B + B_1A}$
= ${16(3 × 6)}/{12 × 6 + 8 × 3}$
= ${16 × 18}/96$ = 3 days
Question : 2
12 men and 16 boys can do a piece of work in 5 days; 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is
a) 1 : 3
b) 2 : 1
c) 3 : 1
d) 5 : 4
Answer »Answer: (b)
Work done by 12 men + 16 boys in 5 days
≡ Work done 13 men + 24 boys in 4 days
(60 men + 80 boys)’s 1 day’s work ≡ (52 men + 96 boys)’s 1 day’s work
(60 - 52) men ≡ (96 - 80) boys
8 men ≡ 16 boys ⇒ 1 man ≡ 2 boys
∴ Required ratio = 2 : 1
Question : 3
A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman alone take to complete the work?
a) 24 days
b) 9 days
c) 21 days
d) 27 days
Answer »Answer: (b)
Work done by 1 woman in 1 day
= $1/3 - 1/6 - 1/18 = {6 - 3 - 1}/18 = 1/9$
Woman will do the work in 9 days.
Using Rule 18A, B and C can do a certain work together within 'x' days. While, any two of them can do the same work separately in 'y' and 'z' days, then in how many days can 3rd do the same work?Required time = ${xyz}/{yz - x(y + z)}$days
Here, x = 3, y = 6 and z = 18
Required time = ${xyz}/{yz - x(y + z)}$ days
= ${3 × 6 × 18}/{6 × 18 - 3(6 + 18)}$
= $324/{108 - 3 24}$
= $324/{108 - 3 × 24} = 324/36$ = 9
Question : 4
If 1 man or 2 women or 3 boys can complete a piece of work in 88 days, then 1 man, 1 woman and 1 boy together will complete it in
a) 48 days
b) 36 days
c) 42 days
d) 54 days
Answer »Answer: (a)
1 man = 2 women ≡ 3 boys 1 man + 1 woman + 1 boy
= $(3 + 3/2 + 1)$ boys = $11/2$ boys
$M_1D_1 = M_2D_2$
$3 × 88 = 11/2 × D_2$
$D_2 = {2 × 3 × 88}/11$ = 48 days
Using Rule 13If A men or B boys or C women can do a certain work in 'a' days, then $A_1$ men, $B_1$ boys and $C_1$ women can do the same work inTime taken = $a/{A_1/A + B_1/B + C_1/C}$
Here, A = 1, B= 2, C = 3, a = 88
$A_1 = 1, B_1 = 1, C_1$ = 1
Time taken = $a/{A_1/A + B_1/B + C_1/C}$
= $88/{1/1 + 1/2 + 1/3}$
= ${88 × 6}/{6 + 3 + 2}$ = 48 days
Question : 5
2 men and 3 women can do a piece of work in 10 days while 3 men and 2 women can do the same work in 8 days. Then, 2 men and 1 woman can do the same work in
a) 13 days
b) 12 days
c) 12$1/2$ days.
d) 13$1/2$ days
Answer »Answer: (c)
2 × 10 men + 3 × 10 women = 3 × 8 men + 2 × 8 women
20 men + 30 women = 24 men + 16 women
4 men = 14 women or 2 men = 7 women
2 men + 3 women = 10 women
2 men + 1 woman = 8 women
$M_1D_1 = M_2D_2$
10 × 10 = 8 × $D_2$
$D_2 = 25/2 = 12{1}/2$ days
Using Rule 11
Here, $A_1 = 2, B_1 = 3, D_1$ = 10
$A_2 = 3, B_2 = 2, D_2$ = 8
$A_3 = 2, B_3$ = 1
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days.
= ${10 × 8(2 × 2 - 3 × 3)}/{10(2 × 1 - 2 × 3) - 8(3 × 1 - 2 × 2)}$
= ${80(4 - 9)}/{10(2 - 6) - 8(3 - 4)}$
= ${-400}/{-40 + 8} = {-400}/{-32} = 25/2 = 12{1}/2$ days
Question : 6
8 children and 12 men complete a certain piece of work in 9 days. Each child takes twice the time taken by a man to finish the work. In how many days will 12 men finish the same work ?
a) 12 days
b) 9 days
c) 13 days
d) 15 days
Answer »Answer: (a)
Using Rule 1,
2 children ≡ 1 man
8 children + 12 men ≡ 16 men
$M_1D_1 = M_2D_2$
16 × 9 = 12 × $D_2$
$D_2 = {16 × 9}/12$ = 12 days.
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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