Model 1 Basic Time & Distance using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 3 hours
(b) 4$5/8$ hours
(c) 2$5/8$ hours
(d) 3$5/8$ hours
The correct answers to the above question in:
Answer: (b)
Speed of train = 60 kmph
Time = 210 minutes
= $210/60$ hours or $7/2$ hours
Distance covered
= $60 × 7/2$ = 210 km
Time taken at 80 kmph
= $210/80 = 21/8$ hours
= 2$5/8$ hours
Using Rule 9,
Here, $S_1 = 60, t_1 = 210/60 hrs, S_2 = 80, t_2$ = ?
$S_1t_1 = S_2t_2$
60 × $210/60 = 80 × t_2$
$t_2 = 21/8$ hrs = 2$5/8$ hrs
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Read more basic problems formulas Based Quantitative Aptitude Questions and Answers
Question : 1
An athlete runs 200 metres race in 24 seconds. His speed (in km/ hr) is :
a) 30
b) 28.5
c) 24
d) 20
Answer »Answer: (a)
Using Rule 1,
Speed = $\text"Distance"/\text"Time"$
= $200/24$ m/s
$200/24$ m/s = $200/24 × 18/5$
= 30 km/h [Since, x m/s = $18/5$ x km/h]
Question : 2
A car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. At 10.30 he finds that he has covered only 40% of the distance. By how much he has to increase the speed of the car in order to keep up his schedule?
a) 30 km/hr
b) 35 km/hr
c) 40 km/hr
d) 45 km/hr
Answer »Answer: (a)
Distance covered by car in2hours
=${300 × 40}/100$ = 120km
Remaining distance
= 300 - 120 = 180 km
Remaining time= 4 - 2= 2 hours
Required speed
=$180/2$= 90kmph
Original speed of car
=$120/2$= 60kmph
Required increase in speed
= 90 - 60 = 30 kmph
Question : 3
A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/ hr. If he takes 5 hours in going and coming, the distance between his house and school is :
a) 6.5 km
b) 5.5 km
c) 5 km
d) 6 km
Answer »Answer: (d)
Let the required distance be x km. Then,
$x/3 + x/2$ = 5
${2x + 3x}/6$ = 5
5x = 6 × 5
x = ${6 × 5}/5$ = 6 km
Using Rule 5,
Here, x = 3, y = 2
Average Speed = ${2 × x × y}/{x + y}$
= ${2 × 3 × 2}/{3 + 2} = 12/5$ km/hr
Total distance = $12/5 × 5$ = 12km
Required distance = $12/2$ = 6 km
Question : 4
Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.
a) 9 km
b) 6 km
c) 7 km
d) 8 km
Answer »Answer: (c)
If the required distance be x km, then
$x/3 - x/4 = 1/2$
${4x - 3x}/12 = 1/2$
$x/12 = 1/2$ ⇒ x = 6 km
Using Rule 9,
Here $S_1 = 4, t_1 = x, S_2 = 3, t_2 = x + 1/2$
$S_1t_1 = S_2t_2$
$4 × x = 3(x + 1/2)$
$4x - 3x = 3/2 x = 3/2$
Distance= $4 × 3/2$ = 6 kms
Question : 5
A man riding his bicycle covers 150 metres in 25 seconds. What is his speed in km per hour ?
a) 20
b) 23
c) 21.6
d) 25
Answer »Answer: (b)
Using Rule 1,
Speed = $150/25$ = 6 m/sec
= $6 × 18/5 = 108/5$ = 21.6 kmph
Question : 6
A train starts from a place A at 6 a.m. and arrives at another place B at 4.30 p.m. on the same day. If the speed of the train is 40 km per hour, find the distance travelled by the train ?
a) 400 km
b) 320 km
c) 230 km
d) 420 km
Answer »Answer: (d)
Using Rule 1,
Time = 10$1/2$ hours = $21/2$ hours
Speed = 40 kmph
Distance = Speed × Time
= $40 × 21/2$ = 420 km
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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