type 1 basic concepts of ratio & proportion Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CGL Prelim 1999]

If x = $1/3$y and y = $1/2$z ,then x : y : z, is equal to :

a) 1 : 3 : 6

b) 2 : 4 : 6

c) 1 : 2 : 6

d) 3 : 2 : 1

Answer: (a)

$x = 1/3y$ ⇒ x : y = 1 : 3

Again, $y = 1/2z$ ⇒ y : z

= 1 : 2 = 3 : 6

x : y : z = 1 : 3 : 6

Question : 17 [SSC CGL Prelim 2000]

If x : y = 3 : 1, then $x^3 - y^3 : x^3 + y^3$ = ?

a) 10 : 11

b) 11 : 10

c) 14 : 13

d) 13 : 14

Answer: (d)

Using Rule 13
Componendo and dividendo - If there is a proportion a:b::c:d then its componendo and dividendo is
(a + b):(a - b)::(c + d):(c - d) or,${a+b}/{a-b}={c+d}/{c-d}$
To simplify the proportion any one method of componendo, dividendo, componendo and Dividendo can directly be used.

$x/y= 3/1 ⇒ x^3/y^3 =27/1$

${x^3 - y^3}/{x^3 + y^3} = {27- 1}/{27 + 1}$

[By componendo and dividendo]

= $26/28 = 13/14$ = 13 : 14

Question : 18 [SSC CGL Prelim 2000]

If a : b = c : d = e : f = 1 : 2, then (pa + qc + re) : (pb + qd + rf) is equal to :

a) 2 : 3

b) 1 : 2

c) (p + q) : r

d) p : (q + r)

Answer: (b)

Using Rule 33,

$a/b = c/d = e/f = 1/2$

${pa}/{pb} = {qc}/{qd} = {re}/{rf}= 1/2$

${pa +qc+ re}/{pb+ qd+ rf} = 1/2$ or 1 : 2

Question : 19 [SSC SO 2007]

If A : B = 2 : 3 and B : C = 4 : 5, then A : B : C is

a) 6 : 4 : 5

b) 8 : 12 : 15

c) 5 : 4 : 6

d) 2 : 3 : 5

Answer: (b)

Using Rule 18(ii),

A : B = 2 : 3

B : C = 4 : 5

A : B : C = 2 × 4 : 3 × 4 : 3 × 5

= 8 : 12 : 15

Question : 20 [SSC CGL Prelim 2005]

If A : B = 3 : 4, B : C = 5 : 7 and C : D = 8 : 9 then A : D is equal to

a) 21 : 10

b) 10 : 21

c) 7 : 3

d) 3 : 7

Answer: (b)

$A : D = A/D =A/B ×B/C× C/D$

= $3/4× 5/7× 8/9 =10/21$= 10 : 21

Using Rule 19
If A:B = x:y, B:C = p:q and C:D = m:n then,
(i) A:D = xpm : yqn
(ii) A:B:C:D = (xp:yp:yq) × m:yqn = xpm:ypm:yqm:yqn

A : D = xpm : yqn

= 3 × 5 × 8 : 4 × 7 × 9

= 10 : 21

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