type 3 addition subtraction product on ratio & proportion Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 21 [SSC CAPFs SI 2013]
If the square of the sum of two numbers is equal to 4 times of their product, then the ratio of these numbers is :
a) 1 : 1
b) 1 : 2
c) 1 : 3
d) 2 : 1
Answer »Answer: (a)
$(x + y)^2 = 4xy$
$x^2 + y^2 + 2xy - 4xy = 0$
$(x - y)^2$ = 0 ⇒ x = y
x : y = 1 : 1
Question : 22 [SSC CPO S.I.2003]
The sum of three numbers is 116. The ratio of second to the third is 9 : 16 and the first to the third is 1 : 4. The second number is
a) 34
b) 36
c) 32
d) 30
Answer »Answer: (b)
Number | II | III | I | ||
9 | : | 16 | |||
4 | : | 1 | |||
36 | : | 64 | : | 16 | |
9 | : | 16 | : | 4 |
Therefore, second number
=$9/{9 +16+4}×116$
=$9/29×116=36$
Question : 23 [SSC CGL Prelim 2002]
The ratio of two numbers is 10 : 7 and their difference is 105. The sum of these numbers is
a) 1190
b) 1610
c) 805
d) 595
Answer »Answer: (d)
Let the nos. be 10x & 7 x then,
10 x - 7x = 105
3x = 105 ⇒ x = 35
Sum = 10x + 7x = 17x
= 17 × 35 = 595
Question : 24 [SSC CGL Tier-I 2016]
Two numbers are in the ratio 3 : 5. If 6 is added to each of them, the ratio becomes 2 : 3. The numbers are
a) 24 and 40
b) 18 and 30
c) 30 and 50
d) 21 and 35
Answer »Answer: (b)
Let the numbers be 3x and 5x.
According to the question,
${3x + 6}/{5x + 6}= 2/3$
10x + 12 = 9x + 18
10x - 9x = 18 - 12
x = 6
Numbers are :
3x = 3 × 6 = 18 and
5x = 5 × 6 = 30
Question : 25 [SSC CGL Tier-II 2013]
Three numbers are in the ratio 2 : 3 : 4. If the sum of their squares is 1856, then the numbers are
a) 12, 18 and 24
b) None of the above
c) 16, 24 and 32
d) 8, 12 and 16
Answer »Answer: (c)
Numbers = 2x, 3x and 4x
$(2x)^2 + (3x)^2 + (4x)^2$ = 1856
$4x^2 + 9x^2 + 16x^2$ = 1856
$29x^2$ = 1856
$x^2$ = 1856 ÷ 29 = 64
$x = √64$ = 8
Numbers = 16, 24 and 32
IMPORTANT quantitative aptitude EXERCISES
-
199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
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Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
type 3 addition subtraction product on ratio & proportion Online Quiz
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