type 3 addition subtraction product on ratio & proportion Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CGL Tier-I 2012]

The number to be added to each of the numbers 7, 16, 43, 79 to make the numbers in proportion is

a) 5

b) 1

c) 3

d) 2

Answer: (a)

From the given options number = 5, because

${7 + 5}/{16 + 5} = {43 + 5}/{79 + 5}$

$12/21 = 48/84$

[check other options likewise]

Using Rule 32,

Here, a = 7, b=16, c = 43, d= 79

Required number

x= ${bc - ad}/{(a+d) - (b+c)}$

= ${16 × 43 - 7 × 79}/{(7 + 79) - (16 + 43)}$

= ${688 - 553}/{86 - 79}$

= $35/7$ = 5

Question : 17 [SSC DEO 2009]

Which number when added to each of the numbers 6, 7, 15, 17 will make the resulting numbers proportional ?

a) 4

b) 3

c) 5

d) 6

Answer: (b)

Let required number be x.

${6 +x}/{7 + x} = {15 + x}/{17 + x}$

$102 + 17x + 6x + x^2$

= $105 + 7x + 15x + x^2$

23x - 22x = 105 - 102

x = 3

Note : It is convenient to solve it orally using options

${6 + 3}/{7 + 3} = {15 + 3}/{17 + 3}$

= $9/10 = 18/20$

Using Rule 32
Let 'x' be a number which is subtracted from a, b, c and d to make them proportional, then
x = ${ad - bc}/{(a+d) - (b+c)}$
Let 'x' be a number which is added to a, b, c and d to make them proportional, then
x = ${bc - ad}/{(a+d) - (b+c)}$
Here, a, b, c and d should always be in ascending order.

Required Number

= ${bc - ad}/{(a+d) - (b+c)}$

Where a = 6, b = 7, c = 15, d = 17

= ${7 × 15 - 6 × 17}/{(6 + 17) - (7 + 15)}$

= ${105 - 102}/{23 - 22}$ = 3

Question : 18 [SSC CGL Tier-I 2015]

If A and B are in the ratio 4 : 5 and the difference of their squares is 81, what is the value of A ?

a) 36

b) 15

c) 12

d) 45

Answer: (c)

Let A = 4x and B = 5x.

According to the question,

$(5x)^2 - (4x)^2$ = 81

$25x^2 - 16x^2$ = 81

$9x^2 = 81 ⇒ x^2$ = 9

$x = √9$ = 3

A = 4x = 4 × 3 = 12

Question : 19 [SSC CGL Tier-I 2010]

Two numbers are in the ratio 1 : 3. If their sum is 240, then their difference is

a) 100

b) 96

c) 108

d) 120

Answer: (d)

Let the numbers be 3x and x,

Then, 3x + x = 240

4x = 240

$x = 240/4$ = 60

Difference = 3x - x = 2x

= 2 × 60 = 120

Question : 20 [SSC CGL Tier-1 2011]

Three numbers are in the ratio 3 : 4 : 5. The sum of the largest and the smallest equals the sum of the second and 52. The smallest number is

a) 39

b) 52

c) 27

d) 20

Answer: (a)

Let the numbers be 3x, 4x and 5x.

5x + 3x = 4x + 52

4x = 52 ⇒ x =13

The smallest number

= 3x = 3 × 13 = 39

IMPORTANT quantitative aptitude EXERCISES

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