model 2 based on simplification Practice Questions Answers Test with Solutions & More Shortcuts
power, indices and surds PRACTICE TEST [5 - EXERCISES]
model 1 find largest and smallest value
model 2 based on simplification
model 3 based on positive and negative exponent
model 4 simplifying roots with values
model 5 simplifying roots of roots
Question : 6 [SSC CPO S.I.2007]
$√{8 - 2 √{15}}$ is equal to :
a) $√5 - √3$
b) $√5 + √3$
c) $3 - √5$
d) $5 - √3$
Answer »Answer: (a)
Expression=$√{8 - 2 √{15}}$
= $√{5+3-2√{5}×√{3}}$
= $√{(√5)^2+(√3)^2-2√5×√3}$
= $√{(√5-√3)^2} = √5-√3$
Question : 7 [SSC CGL Prelim 2004]
$√5/{√3 + √2} - {3√3}/{√5 + √2} + {2√2}/{√5 + √3}$ is equal to :
a) $2√10$
b) 0
c) $2√6$
d) $2√15$
Answer »Answer: (b)
$√5/{√3 + √2} - {3√3}/{√5 + √2} + {2√2}/{√5 + √3}$
$√5/{√3 + √2} = {√5(√3 - √2)}/{(√3 + √2)(√3 - √2)}$
= ${√{15} - √{10}}/{3 - 2} = √{15} - √{10}$
${3√3}/{√5 + √2} = {3√3}/{√5 + √2} × {√5 - √2}/{√5 - √2}$
= ${3√3(√5 - √2)}/{5-2} = √{15} - √6$
${2√2}/{√5 + √3} = {2√2(√5 - √3)}/{(√5 + √3)(√5 - √3)}$
= ${2√2(√5 -√3)}/{5 - 3} = √{10} - √6$
Expression
= $(√{15} - √{10}) - (√{15} - √6) + (√{10} - √6)$
= $√{15} - √{10} - √{15} + √6 + √{10} - √6 = 0$
Question : 8 [SSC CPO S.I.2004]
a) 1.50
b) 1.00
c) 2.25
d) 1.25
Answer »Answer: (b)
$1/{√{3.25} + √{2.25}} + 1/{√{4.25} + √{3.25}} + 1/{√{5.25} + √{4.25}} + 1/{√{6.25} + √{5.25}}$
$1/{√{3.25} + √{2.25}}$
= $1/(√{3.25} + √{2.25})×{{√{3.25} - √{2.25}}/{√{3.25} - √{2.25}}}$
= ${√{3.25} - √{2.25}}/{3.25 - 2.25} = √{3.25} - √{2.25}$
Similarly
$1/{√{4.25} + √{3.25}}= √{4.25} - √{3.25}$
$1/{√{5.25} + √{4.25}}= √{5.25} - √{4.25}$
$1/{√{6.25} + √{5.25}}= √{6.25} - √{5.25}$
Expression
=$√{3.25} - √{2.25} +√{4.25} - √{3.25} +√{5.25} - √{4.25} +√{6.25} - √{5.25}$
= $√{6.25} - √{2.25}$
= 2.5 - 1.5 =1
Question : 9 [SSC CGL Prelim 2007]
$12/{3 + √5 + 2√2}$ is equal to
a) $1 + √5 - √2 + √10$
b) $1 - √5 + √2 + √10$
c) $1 - √5 - √2 + √10$
d) $1 + √5 + √2 - √10$
Answer »Answer: (d)
Expression
= $12/{3 + √5 + 2√2}$
= ${12(3+√5-2√2)}/{[(3+√5)+2√2][(3+√5)-2√2]}$
[Rationalising the denominator]
= ${12(3+√5-2√2)}/{(3+√5)^2- (2√2)^2}$
= ${12(3+√5-2√2)}/{9+5+6√5-8}$
= ${12(3√5-2√2)}/{6√5+6}$
= ${2(3+√5-2√2)}/{√5+1}$
= ${2(3+√5-2√2)(√5-1)}/{(√5+1)(√5-1)}$
= ${2(3√5+5-2√{10}-3-√5+2√2)}/{5-1}$
= ${2(2√5+2√2-2√{10}+2)}/4$
= ${2×2(√5+√2-√{10}+1)}/4$
= $1+√5+√2-√{10}$
Question : 10 [SSC CGL Prelim 2005]
$(16)^{0.16} × (16)^{0.04} × (2)^{0.2}$ is equal to :
a) 4
b) 1
c) 16
d) 2
Answer »Answer: (d)
$(16)^{0.16} × (16)^{0.04} × (2)^{0.2}$
= $(2^4)^{0.16} × (2^4)^{0.04} × (2)^{0.2}$
= $2^{0.64} × 2^{0.16} × 2^{0.2}$
= $(2)^{0.64+0.16+0.2}$ = 2
IMPORTANT quantitative aptitude EXERCISES
model 2 based on simplification Shortcuts »
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Click to Start..power, indices and surds Shortcuts and Techniques with Examples
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model 1 find largest and smallest value
Defination & Shortcuts … -
model 2 based on simplification
Defination & Shortcuts … -
model 3 based on positive and negative exponent
Defination & Shortcuts … -
model 4 simplifying roots with values
Defination & Shortcuts … -
model 5 simplifying roots of roots
Defination & Shortcuts …
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