model 2 divisibility, multiples, add and subtract based number system Practice Questions Answers Test with Solutions & More Shortcuts

Question : 56 [SSC CGL Tier-1 2011]

A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as

a) 3

b) 4

c) 5

d) 2

Answer: (b)

Here, the first divisor i.e. 49 is multiple of second divisor i.e. 7.

∴ Required remainder = Remainder obtained on dividing 32 by 7 = 4

Question : 57

A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first added 12 to the number and then divided it by 6, getting 112 as the answer. The correct answer should have been

a) 122

b) 124

c) 114

d) 118

Answer: (a)

Let the number be x.

∴ ${x + 12} /6$ = 112

⇒ x + 12 = 672

⇒ x = 672 – 12 = 660

∴ Correct answer =${660/6}$ +12

= 110 + 12 = 122

Question : 58

The remainder when $3^21$ is divided by 5 is

a) 2

b) 1

c) 4

d) 3

Answer: (d)

$3^1 = 3; 3^2 = 9; 3^3 = 27; 3^4 = 81; 3^5$ = 243

i.e. unit’s digit is repeated after index 4.

Remainder after dividing 21 by 4 = 1

∴ Unit’s digit in the expansion of $(3)^21$ = 3

∴ Remainder after dividing by 5 = 3

Question : 59 [SSC CGL Tier-I 2010]

A number, when divided by 136, leaves remainder 36. If the same number is divided by 17, the remainder will be

a) 7

b) 9

c) 2

d) 3

Answer: (c)

If the first divisor be a multiple of the second divisor, then required remainder = remainder obtained by dividing the first remainder (36) by the second divisor (17) = 2

Question : 60 [SSC CGL 2007]

When a number is divided by 56, the remainder obtained is 29. What will be the remainder when the number is divided by 8 ?

a) 5

b) 4

c) 7

d) 3

Answer: (a)

+- When the second divisor is factor of first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.

Hence, on dividing 29 by 8, the remainder is 5.

IMPORTANT quantitative aptitude EXERCISES

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