Practice Divide multiple add subtract - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) When a number is divided by 24, the remainder is 16. The remainder when the same number is divided by 12 is
(a)
(b)
(c)
(d)
Required remainder = 16 – 12 = 4
(because 24 is a multiple of 12.)
Q-2) A number consists of two digits. If the number formed by interchanging the digits is added to the original number, the resulting number (i.e. the sum) must be divisible by
(a)
(b)
(c)
(d)
Let the number be 10x + y
After interchanging the digits, the number obtained = 10y + x
According to the question,
Resulting number
= 10x + y + 10y + x
= 11x + 11y
= 11 (x + y) which is exactly divisible by 11.
Q-3) When a number is divided by 893, the remainder is 193. What will be the remainder when it is divided by 47 ?
(a)
(b)
(c)
(d)
Here, 893 is exactly divisible by 47.
Hence, the required remainder is obtained on dividing 193 by 47.
∴ Remainder = 5
Q-4) A number, when divided by 221, leaves a remainder 64. What is the remainder if the same number is divided by 13 ?
(a)
(b)
(c)
(d)
Here, the first divisor (221) is a multiple of second divisor (13)
Hence, required remainder = remainder obtained on dividing 64 by 13 = 12
Q-5) A number when divided by 5 leaves a remainder 3. What is the remainder when the square of the same number is divided by 5 ?
(a)
(b)
(c)
(d)
If the quotient in the first case be x.
Then, number = 5x + 3
On Squaring, the number
= $(5x + 3)^2$
= $25x^2$ + 30x + 9
On dividing by 5, remainder
= 9 – 5 = 4
Q-6) A number when divided by 6 leaves remainder 3. When the square of the same number is divided by 6, the remainder is :
(a)
(b)
(c)
(d)
The remainder will be same. On dividing 9 by 6, remainder = 3 On dividing 81 by 6, remainder = 3
Q-7) When ‘n’ is divisible by 5 the remainder is 2. What is the remainder when $n^2$ is divided by 5 ?
(a)
(b)
(c)
(d)
Required remainder = Remainder obtained by dividing $2^2$ by 5.
Remainder = 4
Q-8) A number being divided by 52 gives remainder 45. If the number is divided by 13, the remainder will be
(a)
(b)
(c)
(d)
Here, 52 is a multiple of 13. Hence, the required remainder is obtained on dividing 45 by 13. Required remainder = 6.
Q-9) A number when divided by 192 gives a remainder of 54. What remainder would be obtained on dividing the same number by 16 ?
(a)
(b)
(c)
(d)
Here, the first divisor 192 is a multiple of second divisor 16.
∴ Required remainder
= remainder obtained by dividing 54 by 16 = 6
Q-10) $9^6$ – 11 when divided by 8 would leave a remainder of :
(a)
(b)
(c)
(d)
If $(x ±1)^n$ is divided by x, the remainder is $(±1)^n$ ,
Now, $9^6$ – 11 == $(8 + 1)^6$ –11
When it is divided by 8,
remainder = + 1 – 11 = – 10
When – 10 is divided by 8,
remainder = – 2 i.e. – 2 + 8 = 6