model 3 find hcf of numbers Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CGL Prelim 2002]

The greatest number, which when divide 989 and 1327 leave remainders 5 and 7 respectively, is :

a) 32

b) 16

c) 8

d) 24

Answer: (d)

Using Rule 7,

(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). )

Required number

= HCF of (989 – 5) and (1327 – 7)

= HCF of 984 and 1320 = 24

∴ HCF = 24

Question : 17 [SSC CGL Prelim 2007]

Three sets of English, Mathematics and Science books containing 336, 240, 96 books respectively have to be stacked in such a way that all the books are stored subject-wise and the height of each stack is the same. Total number of stacks will be

a) 48

b) 21

c) 14

d) 22

Answer: (c)

Number of books in each stack

= HCF of 336, 240, 96 = 48

∴ Total number of stacks

=$336/48 + 240/ 48 + 96/48$

=7 + 5 + 2 = 14

Question : 18 [SSC CGL 2014]

Find the greatest number which will exactly divide 200 and 320.

a) 40

b) 20

c) 10

d) 16

Answer: (a)

Required number = HCF of 200 and 320 = 40

Illustration :

Question : 19 [SSC FCI 2013]

The greatest number that divides 411, 684, 821 and leaves 3, 4 and 5 as remainders, respectively, is

a) 204

b) 146

c) 254

d) 136

Answer: (d)

Using Rule 7,

(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). )

Required number

= HCF of 411 – 3 = 408; 684 – 4 = 680 and 821 – 5 = 816

HCF of 408 and 816 = 408

HCF of 408 and 680

∴ Required number = 136

Question : 20 [SSC CGL Prelim 2005]

What is the greatest number that will divide 307 and 330 leaving remainders 3 and 7 respectively ?

a) 23

b) 16

c) 19

d) 17

Answer: (c)

Using Rule 7,

(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).)

The number will be HCF of

307 – 3 = 304 and 330 – 7 = 323.

∴ Required number = 19

IMPORTANT quantitative aptitude EXERCISES

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