model 3 find hcf of numbers Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CGL 2016]

The product of two 2–digit numbers is 2160 and their H.C.F. is 12. The numbers are

a) (60, 72)

b) (72, 30)

c) (12, 60)

d) (36, 60)

Answer: (d)

HCF of numbers = 12

Let the numbers be 12x and 12y

where x and y are co–prime.

According to the question,

12x × 12y = 2160

⇒ xy = $2160/{ 12×12}$ = 15

= 3 × 5 or 1 × 15

∴ Required numbers

= 12 × 3 = 36 and 12 × 5 = 60

Question : 2 [SSC CGL 2012]

H.C.F of $2/3,4/5$and $6/7$ is

a) $24/105$

b) $2/105$

c) $48/105$

d) $1/105$

Answer: (b)

Using Rule 3,

(H.C.F. of fractions =$\text"H.C.F of numerators"/ \text"L.C.M.of denominators"$)

HCF of $2/3,4/5$and $6/7$

= $\text"H.C.F of 2,4 and 6"/ \text"L.C.M.of 3,5 and 7"$

= $2/105$

Question : 3 [SSC CAPFs 2014]

84 Maths books, 90 Physics books and 120 Chemistry books have to be stacked topicwise. How many books will be there in each stack so that each stack will have the same height too ?

a) 21

b) 18

c) 12

d) 6

Answer: (d)

As the height of each stack is same,

the required number of books in each stack

= HCF of 84, 90 and 120

84 = 2 × 2 × 3 × 7

90 = 2 × 3 × 3 × 5

120 = 2 × 2 × 2 × 3 × 5

∴ HCF = 2 × 3 = 6

Question : 4

Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then, sum of the digits in N is :

a) 8

b) 5

c) 4

d) 6

Answer: (c)

Using Rule 7,

The greatest number N = HCF of (1305 – x ), (4665 – x ) and (6905 – x),

where x is the remainder

= HCF of (4665 – 1305), (6905– 4665) and (6905 – 1305)

= HCF of 3360, 2240 and 5600

∴ N = 1120

Sum of digits = 1 + 1 + 2 + 0 = 4

Question : 5 [SSC CHSL 2014]

There are 24 peaches, 36 apricots and 60 bananas and they have to be arranged in several rows in such a way that every row contains the same number of fruits of only one type. What is the minimum number of rows required for this to happen ?

a) 6

b) 9

c) 12

d) 10

Answer: (d)

Minimum number of rows = Maximum number of fruits in each row

∴ HCF of 24, 36 and 60 = 12

∴ Minimum number of rows

= $24/12 + 36/12 + 60/12$

= 2 + 3 + 5 = 10

IMPORTANT quantitative aptitude EXERCISES

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