model 9 voters & election Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : In an election, a candidate secures 40% of the votes but is defeated by the only other candidate by a majority of 298 votes. Find the total number of votes recorded.

(a) 1470

(b) 1580

(c) 1530

(d) 1490

The correct answers to the above question in:

Answer: (d)

Total votes polled = x

According to the question,

(60 – 40)% of x = 298

$x × 20/100 = 298$

$x/5$ = 298

x = 298 × 5 = 1490

Practice percentage (model 9 voters & election) Online Quiz

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Read more voters election based Based Quantitative Aptitude Questions and Answers

Question : 1

In an election between two candidates, the candidate getting 60% of the votes polled, is elected by a majority of 14,000 votes. The number of votes polled by the winning candidate is

a) 42,000

b) 28,000

c) 46,000

d) 32,000

Answer: (a)

Difference of percentage of votes = 60% – 40% = 20%

20% of total votes = 14000

60% of total votes = $14000/20 × 60$ = 42000

Question : 2

In an election there were only two candidates. One of the candidates secured 40% of votes and is defeated by the other candidate by 298 votes. The total number of votes polled is

a) 1490

b) 745

c) 1500

d) 1460

Answer: (a)

Let votes polled = x

$x × ({60 - 40}/100)$ = 298

$x × 1/5 = 298$

x = 298 × 5 = 1490

Using Rule 26,

If a candidate got A% votes in a poll and he won or defeated by 'x' votes, then,

what was the total no. of votes which was cast in the poll?

∴ Total no. of votes = ${50 × x}/{50 - A}$

Total number of votes = ${50 × 298}/{50 - 40} = 1490$

Question : 3

In an election 10% of the voters on the voters' list did not cast their votes and 60 voters cast their ballot papers blank. There were only two candidates. The winner was supported by 47% of all the voters in the list and he got 308 votes more than his rival. The number of voters on the list was

a) 4575

b) 3600

c) 6028

d) 6200

Answer: (d)

Total voters in the list = x

Votes got by the winner = ${47x}/100$

Votes got by the loser

=$x - x/10 - 60 - {47x}/100$

= ${9x}/10 - {47x}/100 - 60$

= ${90x - 47x}/100 - 60$

= ${43x}/100 - 60$

According to the question,

${47x}/100 - {43x}/100 + 60 = 308$

${4x}/100 = 308 – 60 = 248$

$x = {248 × 100}/4 = 6200$

Question : 4

At an election there were two candidates. A candidate got 38% of votes and lost by 7200 number of votes. The total number of valid votes were

a) 16200

b) 13000

c) 30000

d) 13800

Answer: (c)

Number of valid votes = x (let)

(62 – 38)% of x = 7200

$x × 24/100 = 7200$

$x = {7200 × 100}/24$ = 30000

Using Rule 26,

Total number of votes

= ${50 × 7200}/{(50 - 38)}$

= 50 × 600 = 30000

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