letter or alphabet series Practice Questions Answers Test with Solutions & More Shortcuts

Directions:
In each of the following questions, various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives.

Question : 16 [C.E.T. 2006]

WFB, TGD, QHG, ?

a) NIJ

b) NIK

c) NJK

d) OIK

e) PJK

Answer: (b)

Question : 17 [Bank P.O. 1999]

UPI, ?, ODP, MBQ, IAW

a) RHJ

b) SHJ

c) SIJ

d) THK

e) TIJ

Answer: (b)

Question : 18 [S.S.C. 2002]

AYBZC, DWEXF, GUHVI, JSKTL, ?

a) MQORN

b) MQNRO

c) NQMOR

d) QMONR

Answer: (b)

Question : 19 [I.B.P.S. 2002]

ATTRIBUTION, TTRIBUTIO, RIBUTIO, IBUTI, ?

a) IBU

b) UT

c) UTI

d) BUT

e) None of these

Answer: (c)

In the first step, one letter from the beginning and one from the end of a term are removed to give the next term.

In the second step, two letters from the beginning of a term are removed.

These two steps are repeated alternately.

Question : 20 [UPSC, 2005]

Consider the following series : ABCD ….. XYZ, YX ….. BA,  BCD ….. YZ, YX ….. CBA, BC ….. YZ ….. Which letter occupies the 1000th position in the above series?

a) b

b) c

c) x

d) y

Answer: (a)

We have 3 patterns :

I. ABCD ….. XYZ, which occurs only once.

II. YX ….. BA, which repeats alternately.

III. BC ….. YZ, which repeats alternately.

Now, I has 26 terms.

So, number of terms before the desired term = (999 - 26) = 973.

Each of the patterns which occurs after

I, has 25 letters. Now, 973 + 25 gives quotient = 38 and remainder = 23.

Thus, the 1000th term of the given series is the 24th term of the 39th pattern after I.

Clearly, the 39th pattern is II and its 24th term is B.

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69 series completion based verbal reasoning letter or alphabet series question answer with explanation pdf
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