Alphabet and Numbers Arrangement section 1 MCQ Practice Questions Answers Test with Solutions & More Shortcuts
Alphabet & Numbers Arrangement PRACTICE TEST [6 - EXERCISES]
Alphabet and Numbers Arrangement section 1 MCQ
Alphabet and Numbers Arrangement section 2 MCQ
Alphabet and Numbers Arrangement section 3 MCQ
Alphabet and Numbers Arrangement section 4 MCQ
Alphabet and Numbers Arrangement section 5 MCQ
Alphabet and Numbers Arrangement section 6 MCQ
Directions:
In each of the following questions, two rows of numbers are given. The resultant number in each row is to be worked out separately based on the following rules and the questions below the rows of numbers are to be answered. The operation of numbers progress from the left to the right.
Question : 11
12 | 64 | 17 |
20 | m | 16 |
a) 101
b) 69
c) 85
d) 121
e) None of these
Answer »Answer: (e)
m = $R_1$ | = | 12 | 64 | 17 |
= | 52 | 17 | [Apply Rule (iii)] | |
= | 69 | [Apply Rule (ii)] | ||
Now, $R_2$ | = | 20 | m | 16 |
= | 20 | 69 | 16 | |
= | 89 | 16 | [Apply Rule (ii)] | |
= | 73 | [Apply Rule (v)] |
Question : 12
15 | 8 | 21 |
p | 3 | 27 |
a) 27
b) 58
c) 76
d) 82
e) None of these
Answer »Answer: (b)
$R_1$ | = 15 | 8 | 21 |
= 7 | 21 | [Apply Rule (v)] | |
= 28 | [Apply Rule (i)] | ||
Hence p | =$R_1$ = 28 | ||
Now, $R_2$ | = p | 3 | 27 |
= 28 | 3 | 27 | |
= 31 | 27 | [Apply Rule (ii)] | |
= 58 | [Apply Rule (i)] |
Question : 13
85 | 17 | 35 |
16 | 19 | r |
a) 75
b) 175
c) –5
d) 210
e) None of these
Answer »Answer: (c)
r = $R_1$ | = | 85 | 17 | 35 |
= | 5 | 35 | [Apply Rule (iv)] | |
= | 40 | [Apply Rule (i)] | ||
Now, $R_2$ | = | 16 | 19 | r |
= | 16 | 19 | 40 | |
= | 35 | 40 | [Apply Rule (ii)] | |
= | -5 | [Apply Rule (v)] |
Question : 14
24 | 15 | 3 |
d | 6 | 15 |
a) 22
b) 37
c) 8
d) 29
e) None of these
Answer »Answer: (a)
d = $R_1$ | = | 24 | 15 | 3 |
= | 39 | 3 | [Apply Rule (ii)] | |
= | 13 | [Apply Rule (iv)] | ||
Now, $R_2$ | = | d | 6 | 15 |
= | 13 | 6 | 15 | |
= | 7 | 15 | [Apply Rule (v)] | |
= | 22 | [Apply Rule (i)] |
Question : 15
28 | 49 | 15 |
h | 3 | 12 |
a) 19
b) 12
c) 15
d) 27
e) None of these
Answer »Answer: (d)
h = $R_1$ | = | 28 | 49 | 15 |
= | 21 | 15 | [Apply Rule (iii)] | |
= | 36 | [Apply Rule (i)] | ||
Now, $R_2$ | = | h | 3 | 12 |
= | 36 | 3 | 12 | |
= | 39 | 12 | [Apply Rule (ii)] | |
= | 27 | [Apply Rule (v)] |
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