Practice Clocks comparison - verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1) London time is five and a half hours behind Delhi time. What time is it in London if it is 0.2.35 in Delhi?
(a)
(b)
(c)
(d)
Clearly, time in London is 5 hrs 30 minutes behind 2.35 a.m. which is 9.05 p.m. or 21.05 hrs.
Q-2) Raveena left house for the bus stop 15 min earlier than usual. It takes 10 min to reach the stop. She reached the stop at 8 : 40 am. What time does he usually leave home for the bus stop?
(a)
(b)
(c)
(d)
Clearly, Raveena left home 10 min before 8 : 40 am i.e., at 8 : 30 am
but it was 15 min earlier than usual,
so she usually leaves for the stop at (8 : 30 + 0 : 15) = 8 : 45 am.
Q-3) A bus for Delhi leaves every 30 min from a bus stand. An enquiry clerk, Ram told Shyamlal, a passenger that the bus has already left 10 min ago and the next bus will leave at 9 : 35 am. At what time did the enquiry clerk give this information to Shyamlal?
(a)
(b)
(c)
(d)
(e)
As next bus leaves at 9 : 35 am.
Therefore, Previous bus left at (9 : 35 - 0 : 30) = 9 : 05 am.
The time when enquiry clerk gave this information = 9 : 05 + 0 : 10 = 9 : 15 am.
Q-4) The priest told the devotes, "the bell is rung at regular intervals of 45 min. The last bell was rung 5 min ago. The next bell is due to the rung at 7 : 35 am. At what time did the priest give the information to be devotes?
(a)
(b)
(c)
(d)
Time of ringing last bell = (7 : 45- 0 : 45) = 7 : 00 am.
But it happened 5 min before the priest gave the information to the devotes.
Therefore, Time of giving information = 7 : 00 + 0 : 05 = 7 : 05 am.
Q-5) The train for Chandigarh leaves every two and a half hour from New Delhi Railway Station. An announcement was made at the station that the train for Chandigarh had left 40 min ago and the next train will leave at 18 h. At what time was the announcement made?
(a)
(b)
(c)
(d)
Time of the last train leaving the station = (18 : 00 - 2 : 30) h = 15 : 30 h
But this happens 40 min before the announcement is made.
Therefore, Time of making announcement = (15 : 30 + 0 : 40) = 16 : 10 h.
Q-6) There are two clocks, both set to show 10 pm on 21st January 2010. One clock gains 2 minutes in an hour and the other clock loses 5 minutes in an hour. Then by how many minutes do the two clocks differ at 4 pm on 22nd January 2010?
(a)
(b)
(c)
(d)
One clock show 10 pm.
On 21st January 2010 one clock gains = 2 minutes
Other clock loses = 5 minutes
Time period between 10 pm and 4 pm = 18 hours
Therefore, Required difference = (2 × 18 + 5 × 18) minutes = 126 minutes
Q-7) A bus leaves at 12.25 noon and reaches destination at 10.45 am. The duration of the journey is
(a)
(b)
(c)
(d)
Duration of the journey = (Duration form 12.25 noon to midnight) + (Duration from 12.00 midnight to 10.45 a.m.)
= 11 hrs 35 min + 10 hrs 45 min = 22 hrs 20 min.
Q-8) I have two watches with a 12 hour cycle. One of them gains one minute a day and the other loses 1$1/2$ minute per day. If I set them both at the correct time, how long will it be before they again tell the correct time together?
(a)
(b)
(c)
(d)
Clearly, the first watch will show the correct time when it has gained 12 hours
i.e., (12 × 60) = 720 min and the second watch will show the correct time when it has lost 720 min.
Time taken by first watch to gain 720 min = 720 days.
Time taken by second watch to gain 720 min = (720 ÷ 1 $1/2$) days = (720 × $2/3$ days) = 480 days.
So the first watch shows correct time after every 720 days and the second watch after every 480 days.
Therefore, Time after which both the clocks will together tell the correct time = L.C.M. of 720 and 480 = 1440 days.
Q-9) There are 20 people working in an office. The first group of five works between 8 am and 2 pm. The second group of ten works between 10 am and 4 pm and the third group of five works between 12 noon and 6 pm. There are three computers in the office which all the employees frequently use. During which of the following hours, the computers are likely to be used the most?
(a)
(b)
(c)
(d)
It is obvious that computers would be used most when all the three groups are working simultaneously and this happens during the period 12 noon to 2 pm.
Q-10) Wall clock gains 2 minutes in 12 hours, while a table clock loses 2 minutes every 36 hours. Both are set right at 12 noon on Tuesday. The correct time when both show the same time next would be
(a)
(b)
(c)
(d)
After 12 days, i.e., after 12 × 24 hours clock A will gain 48 minutes and will show 12:48 noon.
After 12 days, i.e., after 12 × 24 hours clock B will lose 16 minutes and will show 11:44 am.
The two clocks will show the same time after 135 days The time difference has to be 12 hours between then = 720 minutes.
A will gain 540 minutes in 135 days. B will lose 180 minutes in 135 days Total 720 minutes.
Further if we consider only time then the problem becomes simpler Total difference of minutes between the times shown by the clocks after 36 hours = $16/3$ minutes difference in 1 day = 12 × 60 minutes difference in $3/16$ × 12 × 60 = 135 days.