Model 2 Train Vs Train in opposite direction Practice Questions Answers Test with Solutions & More Shortcuts
trains PRACTICE TEST [6 - EXERCISES]
Model 1 Train Vs Train in same direction
Model 2 Train Vs Train in opposite direction
Model 3 Train Vs Bridge/Platform
Model 4 Train Vs Pole/Signal Post/Man
Model 5 Train Vs Both platform and a man/a pole
Model 6 Change in speed Vs Change with time travel
Question : 6 [SSC SO 2006]
Two trains are moving on two parallel tracks but in opposite directions. A person sitting in the train moving at the speed of 80 km/hr passes the second train in 18 seconds. If the length of the second train is 1000 m, its speed is
a) 120 km/hr
b) 140 km/hr
c) 150 km/hr
d) 100 km/hr
Answer »Answer: (a)
Let the speed of second train be x m/s.
80 km/h = ${80 × 5}/18$ m/s
According to the question
$1000/{x + {80 × 5}/18}$ = 18
1000 = 18x + 400
x = $600/18$ m/s
= $600/18 × 18/5$ km/h = 120 km/h
Question : 7 [SSC CPO S.I.2005]
Two trains start from stations A and B and travel towards each other at speed of 50 km/hour and 60 km/hour respectively. At the time of their meeting, the second train has travelled 120 km more than the first. The distance between A and B is :
a) 1200 km
b) 1320 km
c) 1440 km
d) 990 km
Answer »Answer: (b)
Let train A start from station A and B from station B.
Let the trains A and B meet after t hours.
Distance covered by train A in t hours = 50t
Distance covered by train B in t hours = 60t km
According to the question,
60t - 50t = 120
t = $120/10$ = 12 hours.
Distance AB = 50 × 12 + 60 × 12
= 600 + 720 = 1320 km
Using Rule 13,From stations A and B, two trains start travelling towards each other at speeds a and b, respectively. When they meet each other, it was found that one train covers distance d more than that of another train. The distance between stations A and B is given as$({a + b}/{a - b}) × d$
Here, a = 60, b = 50, d = 120
Distance between A and B = $({a + b}/{a - b}) × d$
= $({60 + 50}/{60 - 50}) × 120$
= $110/10 × 120$ = 1320 km
Question : 8 [SSC CGL Prelim 2003]
Two trains, one 160 m and the other 140 m long are running in opposite directions on parallel rails, the first at 77 km an hour and the other at 67 km an hour. How long will they take to cross each other?
a) 7$1/2$ seconds
b) 6 seconds
c) 10 seconds
d) 7 seconds
Answer »Answer: (a)
Using Rule 2,Let 'a' metre long train is travelling with the speed 'x' m/s and 'b' metre long train is travelling with the speed 'y' m/s in the opposite direction on parallel path.Then, time taken by the trains to cross each other=$({a + b}/{x - y})$ seconds.
If two trains be moving in opposite directions at rate u and v kmph respectively,
then their relative speed = (u + v) kmph.
Further, if their length be x and y km. then time taken to cross each other
= ${x + y}/{u + v}$ hours.
Here, Total length = 160 + 140 = 300m.
Relative speed = (77 + 67) kmph
= 144 kmph = 144 × $5/18$ m/s or 40 m/sec.
Time = $300/40 = 7{1}/2$ Seconds
Question : 9 [SSC CGL Prelim 2008]
Two trains of equal length, running in opposite directions, pass a pole in 18 and 12 seconds. The trains will cross each other in
a) 15.5 seconds
b) 18.8 seconds
c) 20.2 seconds
d) 14.4 seconds
Answer »Answer: (d)
Using Rule 3,
Let the length of each train be x metre.
Speed of first train = $x/18$ m/sec
Speed of second train = $x/12$ m/sec
When both trains cross each other, time taken
= ${2x}/{x/18 + x/12}$
= ${2x}/{{2x + 3x}/36} = {2x × 36}/{5x}$
= $72/5$ = 14.4 seconds
Question : 10 [SSC MTS 2013]
Two trains start from station A and B and travel towards each other at speed of 16 miles/ hour and 21 miles/ hour respectively. At the time of their meeting, the second train has travelled 60 miles more than the first. The distance between A and B (in miles) is :
a) 496
b) 333
c) 540
d) 444
Answer »Answer: (d)
Let the trains meet after t hours
Then, 21t - 16t = 60
5t = 60 ⇒ t = 12 hours
Distance between A and B
= (16 + 21) × 12
= 37 × 12 = 444 miles
Using Rule 13,From stations A and B, two trains start travelling towards each other at speeds a and b, respectively. When they meet each other, it was found that one train covers distance d more than that of another train. The distance between stations A and B is given as$({a + b}/{a - b}) × d$
Here, a = 21, b = 16, d = 60
Distance between A and B
= $({a + b}/{a - b}) × d$
= $({21 + 16}/{21 - 16}) × 60$
= $37/5 × 60$ = 37 × 12 = 444 miles
IMPORTANT quantitative aptitude EXERCISES
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Top 399+ Trains Based Time and Distance MCQs For BANK SSC »
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New 500+ Aptitude Problems on Train For All BANK SSC Exam »
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Top 499+ Aptitude MCQs on Trains Crossing Bridge/Platform »
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New 500+ Aptitude MCQs on Train Crossing Pole/Post or Man »
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Top 499+ Trains Problems Using Time and Distance For SSC »
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Top 489+ Time And Distance MCQ Problems on Train For BANK »
Model 2 Train Vs Train in opposite direction Shortcuts »
Click to Read...Model 2 Train Vs Train in opposite direction Online Quiz
Click to Start..trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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