Model 4 Working with Man, Woman, Child Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 11 [SSC CHSL 2013]
If 4 men or 6 women can do a piece of work in 12 days working 7 hours a day; how many days will it take to complete a work twice as large with 10 men and 3 women working together 8 hours a day?
a) 8 days
b) 6 days
c) 7 days
d) 10 days
Answer »Answer: (c)
Using Rule 1,
4 men ≡ 6 women
1 men ≡ $6/4 = 3/2$ women
10 men + 3 women
= $10 × 3/2 + 3 = 18$ women
${M_1D_1T_1}/W_1 = {M_2D_2T_2}/W_2$
${6 × 12 × 7}/1 = {18 × D_2 × 8}/W_2$
$D_2 = {6 × 12 × 7 × 2}/{18 × 8}$ = 7 days
Question : 12 [SSC CHSL 2014]
3 men or 7 women can do a piece of work in 32 days. The number of days required by 7 men and 5 women to do a piece of work twice as large is
a) 27
b) 19
c) 21
d) 36
Answer »Answer: (c)
3 men ≡ 7 women
7 men ≡ ${7 × 7}/3 = 49/3$ women
7 men + 5 women = $(49/3 + 5)$ women
= $({49 + 15}/3)$ women = $64/3$ women
${M_1D_1}/W_1 = {M_2D_2}/W_2$
${7 × 32}/1 = {64 × D_2}/{3 × 2}$
$D_2 = {7 × 32 × 3 × 2}/64$ = 21 days
Using Rule 12,
Here, A = 3, B = 7, a = 32
$A_1 = 7, B_1$ = 5
Required time = $a/{A_1/A + B_1/B}$
= $32/{7/3 + 5/7} = 32/64 × 21 = 21/2$
They do the twice work in
$21/2$ × 2 = 21 days
Question : 13 [SSC CGL Tier-I 2012]
3 men and 4 boys can complete a piece of work in 12 days. 4 men and 3 boys can do the same work in 10 days. Then 2 men and 3 boys can finish the work in
a) 8 days
b) 17$1/2$ days
c) 5$5/11$ days
d) 22 days
Answer »Answer: (b)
12(3 men + 4 boys) ≡ 10 (4 men + 3 boys)
36 men + 48 boys = 40 men + 30 boys
4 men = 18 boys ⇒ 2 men = 9 boys
4 men + 3 boys
= 21 boys, who do the work in 10 days and
2 men + 3 boys = 12 boys
$M_1D_1 = M_2D_2$
21 × 10 = 12 × $D_2$
$D_2 = {21 × 10}/12 = 35/2 = 17{1}/2$ days
Using Rule 11,
Here, $A_1 = 3, B_1 = 4, D_1$ = 12
$A_2 = 4, B_2 = 3, D_2$ = 10
$A_3 = 2, B_3$ = 3
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days
= ${12 × 10(3 × 3 - 4 × 4)}/{12(3 × 3 - 2 × 4) - 10(4 × 3 - 2 × 3)}$
= ${120 × - 7}/{12(9 - 8) - 10 × 6}$
= $ {-840}/{-48} = 17{1}/2$ days
Question : 14 [SSC CGL Tier-I 2013]
If 8 men or 12 boys can do a piece of work in 16 days, the number of days required to complete the work by 20 men and 6 boys is
a) 8$1/3$ days
b) 5$1/3$ days
c) 6$1/3$ days
d) 7$1/3$ days
Answer »Answer: (b)
8 men ≡ 12 boys ⇒ 4 men ≡ 6 boys
20 men ≡ 30 boys
20 men + 6 boys = 36 boys
$M_1D_1 = M_2D_2$
12 × 16 = 36 × $D_2$
$D_2 = {12 × 16}/36 = 16/3 = 5{1}/3$ days
Using Rule 12,
Here, A = 8, B = 12, a = 16
$A_1 = 20, B_1$ = 6,
Required number of days = $a/{A_1/A + B_1/B} = 16/{20/8 + 6/12}$
= $16/{5/2 + 1/2} = {16 × 2}/6 = 5{1}/3$ days
Question : 15 [SSC CGL Tier-I 2013]
2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1 boy do the work ?
a) 12$1/2$ days
b) 8 days
c) 7 days
d) 2 days
Answer »Answer: (a)
According to the question,
20 men + 30 boys = 24 men + 16 boys
4 men = 14 boys ⇒ 2 men = 7 boys
2 men + 1 boy = 8 boys
2 men + 3 boys = 10 boys
By $M_1D_1 = M_2D_2$
10 × 10 = 8 × $D_2$
$D_2 = {10 × 10}/8 = 25/2 =12{1}/2$ days
Using Rule 11,
Here, $A_1 = 2, B_1 = 3, D_1 = 10$
$A_2 = 3, B_2 = 2, D_2$ = 8
$A_3 = 2, B_3$ = 1
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days
= ${10 × 8(2 × 2 - 3 × 3)}/{10(2 × 1 - 2 × 3) - 8(3 × 1 - 2 × 2)}$
= ${80 × -5}/{-40 + 8} = 12{1}/2$ days
IMPORTANT quantitative aptitude EXERCISES
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Top 199+ Time and Work Efficiency Based Aptitude MCQ Quiz »
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New 299+ Time and Work Aptitude Test On Individual Wages »
Model 4 Working with Man, Woman, Child Shortcuts »
Click to Read...Model 4 Working with Man, Woman, Child Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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