Model 7 Working with individual wages Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CAPFs SI, CISF ASI 2014]

Seventy-five men are employed to lay down a railway line in 3 months. Due to certain emergency conditions, the work was to be finished in 18 days. How many more men should be employed to complete the work in the desired time ?

a) 375

b) 350

c) 300

d) 325

Answer: (c)

Using Rule 1,

$M_1D_1 = M_2D_2$

75 × 90 = $M_2$ × 18

$M_2 = {75 × 90}/18 = 375$

Number of additional men

= 375 - 75 = 300

Question : 22 [SSC CPO S.I.2003]

39 persons can repair a road in 12 days working 5 hours a day. In how many days will 30 persons working 6 hours a day complete the work ?

a) 15 days

b) 14 days

c) 10 days

d) 13 days

Answer: (d)

Less persons, more days (Indirect)

More working hours/day, less days (Indirect)

Let required no. of days be x.

PersonsWorking hours /dayDays
39512
306x

∴ ${30 : 39}/{6 : 5}]$ : : 12 : x

30 × 6 × x = 39 × 5 × 12

$x = {39 × 12 × 5}/{30 × 6}$ = 13 days

Using Rule 1
If $M_1$ men can finish $W_1$ work in $D_1$ days and $M_2$ men can finish $W_2$ work in $D_2$ days then, Relation is
${M_1D_1}/{W_1} = {M_2D_2}/{W_2}$ and
If $M_1$ men finish $W_1$ work in $D_1$ days, working $T_1$ time each day and $M_2$ men finish $W_2$ work in $D_2$ days, working $T_2$ time each day, then
${M_1D_1T_1}/{W_1} = {M_2D_2T_2}/{W_2}$

Here, $M_1 = 39, D_1 = 12, T_1$ = 5

$M_2 = 30, D_2 = ?, T_2$ = 6

$M_1D_1T_1 = M_2D_2T_2$

39 × 12 × 5 = 30 × $D_2$ × 6

$D_2 = {39 × 12 × 5}/{30 × 6}$ = 13 days

Question : 23 [SSC Constable (GD) 2012]

Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of the work in

a) 3 days

b) 5 days

c) 9 days

d) 6 days

Answer: (a)

Using Rule 1,

${M_1D_1}/W_1 = {M_2D_2}/W_2$

${M × 12}/W = {2M × D_2}/{W/2}$

${M × 12}/W = {4MD_2}/W$

$D_2$ = 3 days

Question : 24 [SSC CGL Prelim 2004]

4 mat-weavers can weave 4 mats in 4 days. At the same rate how many mats would be woven by 8 mat-weavers in 8 days ?

a) 16

b) 12

c) 4

d) 8

Answer: (a)

Using Rule 1,

WeaverDaysMats
444
88x

∴ ${4 : 8}/{4 : 8}]$ : : 4 : x

where, x is no. of mats

4 × 4 × x = 8 × 8 × 4

$x = {8 × 8 × 4}/{4 × 4}$ = 16

Question : 25 [SSC CGL Prelim 2003]

A wall of 100 metres can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a wall of 600 metres ?

a) 30

b) 25

c) 15

d) 20

Answer: (c)

Using Rule 1,

7 men ≡ 10 women

or 1 man = $10/7$ women

14 men + 20 women

= $({10 × 14}/7 + 20)$ women = 40 women

Now, more work, more days

More women, less days

∴ ${Work - {1 : 6}}/{Women - {40 : 10}}]$ : : 10 : x

Where x = number of days

1 × 40 × x = 6 × 10 × 10

or $x = 600/40$ = 15

IMPORTANT quantitative aptitude EXERCISES

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