type 1 basic simple interest using formula Practice Questions Answers Test with Solutions & More Shortcuts
simple interest PRACTICE TEST [6 - EXERCISES]
type 1 basic simple interest using formula
type 2 increase or decrease in interest rate
type 3 money multiples in ‘n’ years
type 4 difference & equality of si rate & years
type 5 si on ‘n’ years & ‘x/y ‘of sum
type 6 si with ratios
Question : 16 [SSC CGL Prelim 2005]
A person borrows Rs.5,000 for 2 years at 4% per annum simple interest. He immediately lends it to another person at 6$1/4$% per annum simple interest for 2 years. His gain in the transaction is
a) Rs.450
b) Rs.112.50
c) Rs.150
d) Rs.225
Answer »Answer: (d)
Using Rule 1,
Case I :
S.I. = ${5000 × 2 × 4}/100$ = Rs.400
Case II :
S.I. = ${5000 × 25 × 2}/{100 × 4}$ = Rs.625
Gain = Rs.(625 - 400) = Rs.225
Question : 17 [SSC DEO 2009]
In how many years will a sum of Rs.3,000 yield a simple interest of Rs.1,080 at 12% per annum ?
a) 2$1/2$ years
b) 3 years
c) 3$1/2$ years
d) 2 years
Answer »Answer: (b)
Using Rule 1,
Time = ${SI × 100}/{\text"Principal × Rate"$
= ${1080 × 100}/{3000 × 12} = 3$ years
Question : 18 [SSC CHSL 2010]
A sum of money amounts to Rs.850 in 3 years and to Rs.925 in 4 years at some rate of simple interest. The sum is :
a) Rs.600
b) Rs.550
c) Rs.700
d) Rs.625
Answer »Answer: (d)
Interest for 1 year
= Rs.(925 - 850) = Rs.75
If a sum becomes $a_1$ in $t_1$ years and $a_2$ in $t_2$ years then rate of interest
= ${100(a_2 - a_1)}/({a_1t_2 - a_2t_1})%$
= ${100(925 - 850)}/{850 × 4 - 3 × 925} = 7500/625$ = 12%
Principal = ${SI × 100}/{\text"Time × Rate"$
= ${75 × 100}/{1 × 12}$ = Rs.625
Using Rule 12,
P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$
= ${925 × 3 - 850 × 4}/{3 - 4}$
= ${2775 - 3400}/{-1}$
= ${- 625}/{- 1}$ = Rs.625
Question : 19 [SSC CPO S.I.2008]
A sum of money at some rate of simple interest amounts to Rs.2,900 in 8 years and to Rs.3,000 in 10 years. The rate of interest per annum is
a) 2$1/2$%
b) 4%
c) 2%
d) 3%
Answer »Answer: (c)
Principal + interest for 8 years= Rs.2900... (i)
Principal + interest for 10 years = Rs.3000 ... (ii)
Subtracting equation (i) from (ii)
Interest for 2 years = Rs.100
Interest for 8 years
= $100/2 × 8$ = Rs.400
From equation (i),
Principal = Rs.(2900 - 400) = Rs.2500
Rate = ${S.I × 100}/{\text"Time × Principal"}$
= ${400 × 100}/{8 × 2500} = 2%$
Using Rule 12,
R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100
= $({2900 - 3000}/{3000 × 8 - 2900 × 10})$ × 100
=$({- 100}/{24000 - 29000}) × 100$
= ${-100}/{-5000}$ × 100 = 2%
Question : 20 [SSC CGL Prelim 2003]
A lends Rs.2500 to B and a certain sum to C at the same time at 7% annual simple interest. If after 4 years, A altogether receives Rs.1120 as interest from B and C, the sum lent to C is
a) Rs.6500
b) Rs.700
c) Rs.1500
d) Rs.4000
Answer »Answer: (c)
Using Rule 1,
Let the sum lent to C be x
According to the question,
${2500 × 7 × 4}/100 + {x × 7 × 4}/100 = 1120$
or 2500 × 28 + 28x = 112000
or 2500 + x = 4000
or x = 4000 - 2500 = 1500
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type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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