type 1 basic simple interest using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on simple interest topic of quantitative aptitude

Questions : In how many years will a sum of Rs.3,000 yield a simple interest of Rs.1,080 at 12% per annum ?

(a) 2$1/2$ years

(b) 3 years

(c) 3$1/2$ years

(d) 2 years

The correct answers to the above question in:

Answer: (b)

Using Rule 1,

Time = ${SI × 100}/{\text"Principal × Rate"$

= ${1080 × 100}/{3000 × 12} = 3$ years

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Read more basic problems using formula Based Quantitative Aptitude Questions and Answers

Question : 1

A sum of money amounts to Rs.850 in 3 years and to Rs.925 in 4 years at some rate of simple interest. The sum is :

a) Rs.600

b) Rs.550

c) Rs.700

d) Rs.625

Answer: (d)

Interest for 1 year

= Rs.(925 - 850) = Rs.75

If a sum becomes $a_1$ in $t_1$ years and $a_2$ in $t_2$ years then rate of interest

= ${100(a_2 - a_1)}/({a_1t_2 - a_2t_1})%$

= ${100(925 - 850)}/{850 × 4 - 3 × 925} = 7500/625$ = 12%

Principal = ${SI × 100}/{\text"Time × Rate"$

= ${75 × 100}/{1 × 12}$ = Rs.625

Using Rule 12,

P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$

= ${925 × 3 - 850 × 4}/{3 - 4}$

= ${2775 - 3400}/{-1}$

= ${- 625}/{- 1}$ = Rs.625

Question : 2

A sum of money at some rate of simple interest amounts to Rs.2,900 in 8 years and to Rs.3,000 in 10 years. The rate of interest per annum is

a) 2$1/2$%

b) 4%

c) 2%

d) 3%

Answer: (c)

Principal + interest for 8 years= Rs.2900... (i)

Principal + interest for 10 years = Rs.3000 ... (ii)

Subtracting equation (i) from (ii)

Interest for 2 years = Rs.100

Interest for 8 years

= $100/2 × 8$ = Rs.400

From equation (i),

Principal = Rs.(2900 - 400) = Rs.2500

Rate = ${S.I × 100}/{\text"Time × Principal"}$

= ${400 × 100}/{8 × 2500} = 2%$

Using Rule 12,

R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100

= $({2900 - 3000}/{3000 × 8 - 2900 × 10})$ × 100

=$({- 100}/{24000 - 29000}) × 100$

= ${-100}/{-5000}$ × 100 = 2%

Question : 3

A lends Rs.2500 to B and a certain sum to C at the same time at 7% annual simple interest. If after 4 years, A altogether receives Rs.1120 as interest from B and C, the sum lent to C is

a) Rs.6500

b) Rs.700

c) Rs.1500

d) Rs.4000

Answer: (c)

Using Rule 1,

Let the sum lent to C be x

According to the question,

${2500 × 7 × 4}/100 + {x × 7 × 4}/100 = 1120$

or 2500 × 28 + 28x = 112000

or 2500 + x = 4000

or x = 4000 - 2500 = 1500

Question : 4

A person borrows Rs.5,000 for 2 years at 4% per annum simple interest. He immediately lends it to another person at 6$1/4$% per annum simple interest for 2 years. His gain in the transaction is

a) Rs.450

b) Rs.112.50

c) Rs.150

d) Rs.225

Answer: (d)

Using Rule 1,

Case I :

S.I. = ${5000 × 2 × 4}/100$ = Rs.400

Case II :

S.I. = ${5000 × 25 × 2}/{100 × 4}$ = Rs.625

Gain = Rs.(625 - 400) = Rs.225

Question : 5

A sum of money at simple interest amounts to Rs.1,012 in 2$1/2$ years and to Rs.1,067.20 in 4 years. The rate of interest per annum is :

a) 3%

b) 2.5%

c) 5%

d) 4%

Answer: (d)

Principal + S.I. for $5/2$ years = Rs.1012 ...(i)

Principal + S.I. for 4 years = Rs.1067.20 ...(ii)

Subtracting equation (i) from (ii)

S.I. for $3/2$ years = Rs.55.20

S.I. for $5/2$ years

= $55.20 × 2/3 × 5/2$ = Rs.92

Principal

= Rs.(1012 - 92) = Rs.920

Rate = ${92 × 100}/{920 × 5/2}$

= ${2 × 92 × 100}/{920 × 5}$ = 4%

Using Rule 12,

R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100

= $({1012 - 1067.20}/{1067.20 × 5/2 - 1012 × 4}) × 100$

= ${- 55.2}/({2668 - 4048}) × 100$

= ${- 55.2}/{- 1380} × 100$ = 4%

Question : 6

A man lent Rs.60,000, partly at 5% and the rest at 4% simple interest. If the total annual interest is Rs.2560, the money lent at 4% was

a) Rs.44000

b) Rs.40000

c) Rs.45000

d) Rs.30000

Answer: (a)

Using Rule 1
Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ or
S.I. = ${\text"P × R × T"/100$
P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$
A = P + S.I. or S.I. = A - P

Let the amount lent at 4% be x

Amount lent at 5% = (60000 - x )

According to the question,

${(60000 - x) × 5 × 1}/100 + {x × 4 × 1}/100$ = 2560

300000 - 5x + 4x = 256000

x = 300000 - 256000 = Rs.44000

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