type 7 finding sum difference product based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 26 [SSC CGL Tier-I 2014]
What number should be subtracted from both the terms of the ratio 11 : 15 so as to make it as 2 : 3 ?
a) 4
b) 5
c) 3
d) 2
Answer »Answer: (c)
Required number = x
${11 - x}/{15 - x} = 2/3$
33 - 3x = 30 - 2x
3x - 2x = 33 - 30
x = 3
Question : 27 [SSC CGL Tier-I 2016]
If the ratio of two numbers is 1 : 5 and their product is 320, then the difference between the squares of these two numbers is :
a) 1536
b) 1435
c) 1256
d) 1024
Answer »Answer: (a)
Let the numbers be x and 5x.
According to the question,
x × 5x = 320
$5x^2$ = 320
$x^2 = 320/5$ = 64
$x = √64$ = 8
Required difference
= $(5x)^2 - x^2$
= $25x^2 - x^2 = 24x^2$
= 24 × 8 × 8 = 1536
Question : 28 [SSC CGL Tier-1 2011]
What number should be added to or subtracted from each term of the ratio 17 : 24 so that it becomes equal to 1 : 2 ?
a) 7 is added
b) 10 is subtracted
c) 10 is added
d) 5 is subtracted
Answer »Answer: (b)
Let the number x be added.
${17 + x}/{24 + x} = 1/2$
34 + 2x = 24 + x
2x - x = 24 - 34
x = - 10
Hence, 10 should be subtracted.
Question : 29 [SSC CGL Tier-II 2016]
The ratio of number of boys to the number of girls in a school of 432 pupils is 5 : 4. When some new boys and girls are admitted, the number of boys increase by 12 and the ratio of the boys to girls changes to 7 : 6. The number of new girls admitted is
a) 24
b) 20
c) 14
d) 12
Answer »Answer: (a)
Original number of boys in school
= $5/9$ × 432 = 240
Number of girls
= 432 - 240 = 192
Let the new number of girls be x.
According to the question,
${240 + 12}/{192 + x} = 7/6$
$252/{192 + x} = 7/6$
192 × 7 + 7x = 252 × 6
1344 + 7x = 1512
7x = 1512 - 1344 = 168
$x = 168/7$ = 24
Question : 30 [SSC Investigator 2010]
Two numbers are in the ratio 3 : 5. If each number is increased by 10, the ratio becomes 5 :7. The smaller number is
a) 15
b) 25
c) 12
d) 9
Answer »Answer: (a)
Let the numbers be 3x and 5x.
${3x + 10}/{5x + 10} = 5/7$
25x + 50 = 21x + 70
4x = 20 ⇒ x = 5
Smaller number
= 3x = 3 × 5 = 15
Using Rule 34,
Here, a = 3, b = 5, c = 5, d = 7, x = 10
Smallest number = ${xa(c-d)}/{ad-bc}$ a < b
= ${10 × 3(5 - 7)}/{3 × 7 - 5 × 5}$
= ${- 60}/{21 - 25} = 60/4$ = 15
IMPORTANT quantitative aptitude EXERCISES
-
199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
-
Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
-
159+ Ratios Proportions Addition Subtraction product MCQ »
-
199+ Ratio Proportion Income, Expenditure Problems MCQS »
-
199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
-
259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
-
199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
-
249+ Ratio and Proportion Coins Based Questions Answers »
type 7 finding sum difference product based ratio & proportion problems Online Quiz
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